To find the area of the polygon shown in the graph, we can use the Shoelace theorem (also known as Gauss's area formula for polygons), which is a straightforward method for computing the area of a simple polygon when the vertices are known.

First, we need to determine the coordinates of the vertices of the polygon. From the graph, we can identify the coordinates of the vertices as follows:

1. (1, 3)
2. (1, 6)
3. (4, 6)
4. (4, 3)
5. (3, 3)
6. (2, 3)
7. (3, 4)
8. (2, 4)

Next, we apply the Shoelace theorem:

The formula is: $\text{Area} = \frac{1}{2} \left| \sum_{i=1}^{n-1} (x_i y_{i+1} - y_i x_{i+1}) + (x_n y_1 - y_n x_1) \right|$

Using the coordinates listed:

1. (1, 3)
2. (1, 6)
3. (4, 6)
4. (4, 3)
5. (3, 3)
6. (2, 3)
7. (3, 4)
8. (2, 4)

We calculate: $\text{Area} = \frac{1}{2} \left| (1*6 + 1*6 + 4*3 + 4*3 + 3*3 + 2*4 + 3*4 + 2*3) - (3*1 + 6*4 + 6*4 + 3*3 + 3*2 + 3*3 + 4*2 + 4*1) \right|$

Breaking it down:

$\text{Sum of products of coordinates} = 6 + 6 + 12 + 12 + 9 + 8 + 12 + 6 = 71$

$\text{Sum of products of reverse coordinates} = 3 + 24 + 24 + 9 + 6 + 9 + 8 + 4 = 87$

$\text{Area} = \frac{1}{2} \left| 71 - 87 \right| = \frac{1}{2} \left| -16 \right| = \frac{1}{2} * 16 = 8$

So, the area of the polygon is $8$ square units.

Would you like more details or have any questions?

Here are 5 questions you might want to ask:

1. How does the Shoelace theorem work for more complex polygons?
2. Can you explain another example of finding the area using the Shoelace theorem?
3. What are the limitations of the Shoelace theorem?
4. How can I calculate the area of irregular shapes that don’t have straight sides?
5. How is the Shoelace theorem derived?

Tip: When using the Shoelace theorem, always list the vertices in a consistent order, either clockwise or counterclockwise, to ensure accurate calculations.