Child tickets cost $3 and adult. tickets cost $5. If the school sells x child tickets and y adult tickets, then the equation. **3x + 5y = 500** expresses the fact that the school raised exactly $500 from ticket sales. solve the eqation for x

We are given the equation:

\[
3x + 5y = 500
\]

To solve for $ x $, follow these steps:

1. Subtract $ 5y $ from both sides of the equation:

\[
3x = 500 - 5y
\]

2. Now, divide both sides by 3 to isolate $ x $:

\[
x = \frac{500 - 5y}{3}
\]

So, the solution for $ x $ is:

\[
x = \frac{500 - 5y}{3}
\]

Would you like more details or have any questions?

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Here are 5 related questions to extend your understanding:

1. How many child tickets were sold if 20 adult tickets were sold?
2. What happens to the value of $ x $ if no adult tickets are sold?
3. How can we represent the number of adult tickets sold if all tickets raised exactly $500?
4. If the school wants to raise $600 instead of $500, how does the equation change?
5. How would you graph the equation $ 3x + 5y = 500 $?

**Tip:** Always check if your solution makes sense by substituting the values back into the original equation.

Child tickets cost $3 and adult tickets cost $5. If the school sells x child tickets and y adult tickets, then the equation 3x + 5y = 500 expresses the fact that the school raised exactly $500 from ticket sales. Solve the equation for x.

Learn how to solve the linear equation 3x + 5y = 500 to find the number of child tickets sold when given the number of adult tickets. This problem involves key algebraic concepts like solving for variables and understanding ticket pricing. Suitable for students in Grades 6-8.

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