Math Problem Statement
Solution
Let's define variables to represent the number of adult and child tickets sold:
- Let represent the number of adult tickets sold.
- Let represent the number of child tickets sold.
We are given the following information:
-
The total number of tickets sold is 212, so:
-
The total revenue generated is $1,080.50. Each adult ticket costs $6.85, and each child ticket costs $3.90, so:
We now have a system of two equations:
x + y &= 212 \\ 6.85x + 3.90y &= 1080.50 \end{aligned}$$ ### Solving this system: 1. Solve the first equation for $$y$$: $$y = 212 - x$$ 2. Substitute this expression for $$y$$ into the second equation: $$6.85x + 3.90(212 - x) = 1080.50$$ 3. Expand and solve for $$x$$: $$6.85x + 3.90 \times 212 - 3.90x = 1080.50$$ $$6.85x + 826.80 - 3.90x = 1080.50$$ $$(6.85x - 3.90x) + 826.80 = 1080.50$$ $$2.95x + 826.80 = 1080.50$$ $$2.95x = 1080.50 - 826.80$$ $$2.95x = 253.70$$ $$x = \frac{253.70}{2.95}$$ $$x \approx 86$$ 4. Substitute $$x = 86$$ back into the first equation: $$86 + y = 212$$ $$y = 212 - 86$$ $$y = 126$$ ### Solution: - 86 adult tickets were sold. - 126 child tickets were sold. Would you like further details on the solution or any clarifications? Here are some related questions: 1. What would the revenue be if all tickets were adult tickets? 2. How much more revenue is generated per adult ticket compared to a child ticket? 3. What is the percentage of child tickets sold out of the total? 4. If the ticket prices changed, how would the equations be adjusted? 5. How could you verify this solution using a different method? **Tip:** When solving systems of equations, substitution and elimination methods are useful depending on the situation.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Algebra
Linear Equations
Systems of Equations
Formulas
x + y = total tickets
6.85x + 3.90y = total revenue
Theorems
Substitution Method for Solving Systems of Equations
Suitable Grade Level
Grades 8-10
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