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Let's break down the problem:

- Clara initially has some number of attires, say \( x \).
- She lends half of her collection to her sister Susan, so she is left with \( \frac{x}{2} \) attires.
- Then, Clara buys 4 more attires. So now she has \( \frac{x}{2} + 4 \) attires.
- According to the problem, Clara now has 12 attires. Therefore, we can set up the equation:

\[
\frac{x}{2} + 4 = 12
\]

### Solving for \( x \):

1. Subtract 4 from both sides:

\[
\frac{x}{2} = 12 - 4
\]
\[
\frac{x}{2} = 8
\]

2. Multiply both sides by 2 to solve for \( x \):

\[
x = 8 \times 2
\]
\[
x = 16
\]

Thus, Clara originally had **16 attires**.

Would you like further clarification on any steps? Here are some related questions to explore:

1. If Clara had lent a third of her attires instead of half, how would the solution change?
2. What if Clara had bought 6 attires instead of 4? How many attires would she have had initially?
3. How would the equation differ if she had 10 attires after lending and buying more?
4. What would happen if Susan returned all the attires after Clara's purchase?
5. How many attires would Susan have after Clara lent them to her?

**Tip**: When dealing with word problems, translating the situation into an equation is key to solving the problem accurately.

Clara lends half her collection of formal attires to her sister, Susan. Clara then buys four more attires. If she has 12 attires now, how many attires did Clara have initially?

Learn how to solve a word problem involving linear equations, where Clara lends half of her attires to her sister and buys more. This solution explains how to find the initial number of attires Clara had, using algebraic steps suitable for Grades 6-8.

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