Hari buys 1 sweater and 2 shirts. The cost of each shirt is Rs.600 less than the sweater. If he pays Rs.2700 in total, how much does he pay for the sweater?

Let's denote the cost of the sweater as \( S \) (in rupees).

The cost of each shirt is Rs. 600 less than the sweater. So, the cost of each shirt is \( S - 600 \) rupees.

Hari buys 1 sweater and 2 shirts. The total cost he pays is Rs. 2700.

We can set up the equation as follows:
\[
S + 2(S - 600) = 2700
\]

Simplify the equation:
\[
S + 2S - 1200 = 2700
\]

Combine like terms:
\[
3S - 1200 = 2700
\]

Add 1200 to both sides to isolate the term with \( S \):
\[
3S = 3900
\]

Divide both sides by 3:
\[
S = 1300
\]

Therefore, Hari pays Rs. 1300 for the sweater.

Do you want more details or have any questions?

Here are some additional questions you might be interested in:
1. How to determine the cost of each shirt in this scenario?
2. How to set up equations for problems involving multiple items and prices?
3. What are the steps to isolate variables in algebraic equations?
4. How to verify the solution by substituting values back into the original equation?
5. How to solve similar word problems involving costs and quantities?

**Tip:** When solving word problems, clearly define variables and translate the problem's language into mathematical equations step by step.

Learn how to solve the problem where Hari buys 1 sweater and 2 shirts, with specific details on calculating the cost of the sweater. This problem involves setting up and solving linear equations in algebra, suitable for students in Grades 7-9.

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