The given equation is written as:

\[
8x + 2 = 72 + x
\]

We can solve for \( x \) by following these steps:

1. **Move all \( x \)-terms to one side**: Subtract \( x \) from both sides.
   \[
   8x - x + 2 = 72
   \]
   Simplifying:
   \[
   7x + 2 = 72
   \]

2. **Move the constant term to the other side**: Subtract 2 from both sides.
   \[
   7x = 72 - 2
   \]
   Simplifying:
   \[
   7x = 70
   \]

3. **Solve for \( x \)**: Divide both sides by 7.
   \[
   x = \frac{70}{7}
   \]
   Simplifying:
   \[
   x = 10
   \]

Thus, the solution is \( x = 10 \).

Would you like further details or have any questions?

Here are 5 related questions:
1. What happens if we add or subtract a different constant on both sides of the equation?
2. How can we solve for \( x \) in an equation with two variables?
3. How would you solve \( 8x + 2 = k + x \), where \( k \) is an unknown constant?
4. What is the importance of isolating \( x \) when solving linear equations?
5. How would the equation change if one side had a quadratic term?

**Tip:** Always ensure that the variable terms are grouped on one side of the equation, and the constants on the other side, to simplify solving.

Learn how to solve the linear equation 8x + 2 = 72 + x using basic algebraic steps. This guide covers key concepts like moving terms, simplifying, and isolating the variable. Suitable for students in Grades 7-8, this example strengthens understanding of linear equations.

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