Math Problem Statement

3−|y/2+3|>7

Solution

Let's solve the inequality 3y2+3>73 - \left| \frac{y}{2} + 3 \right| > 7.

Step 1: Isolate the absolute value

First, subtract 3 from both sides:

3y2+33>733 - \left| \frac{y}{2} + 3 \right| - 3 > 7 - 3

This simplifies to:

y2+3>4-\left| \frac{y}{2} + 3 \right| > 4

Step 2: Eliminate the negative sign

Dividing both sides by 1-1 (and flipping the inequality sign):

y2+3<4\left| \frac{y}{2} + 3 \right| < -4

Step 3: Interpret the result

Since the absolute value of any expression is always non-negative, it can never be less than a negative number. Therefore, there are no solutions to this inequality.

Conclusion:

The inequality 3y2+3>73 - \left| \frac{y}{2} + 3 \right| > 7 has no solution.


Do you have any questions or would you like further details?

Here are some related questions to explore:

  1. What happens if the inequality is 3y2+373 - \left| \frac{y}{2} + 3 \right| \geq 7?
  2. How would the solution change if the absolute value inequality were positive?
  3. Can you explain how absolute values are handled in inequalities?
  4. How does flipping an inequality sign work when dividing by negative numbers?
  5. Can this problem be rewritten using a different variable for practice?

Tip: Always remember to check if absolute values lead to impossible conditions, especially when comparing them to negative numbers.

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Math Problem Analysis

Mathematical Concepts

Absolute Value Inequalities
Linear Inequalities

Formulas

|x| < c
Inequality Rule: Divide by negative flips the inequality

Theorems

Properties of Absolute Values
No solution condition when absolute value < negative number

Suitable Grade Level

Grades 8-10