Math Problem Statement

explain

Solve the limit problem involving indeterminate forms as x approaches 1/2

Solution

The image you provided contains a mathematical solution related to limits and indeterminate forms, written in Arabic. I will break it down step by step, translating and explaining the key concepts.


Explanation of the Image:

1. Top Right - عنوان: "لتحدد النهاية"

This translates to: "To find the limit"

The task here is to find the limit of a function as x12x \to \frac{1}{2}.

2. Top Limit Equation:

limx12x+312x\lim_{x \to \frac{1}{2}} \frac{x + 3}{1 - 2x}

This is a limit problem, and we need to evaluate it by substituting x=12x = \frac{1}{2} into the expression. However, we see from the next steps that the function 12x1 - 2x goes to 0 at x=12x = \frac{1}{2}, leading to a potential indeterminate form 00\frac{0}{0}.

3. Simplified Calculation:

  • The image shows:

    limx12(12x)=0\lim_{x \to \frac{1}{2}} (1 - 2x) = 0 limx12(x+3)=72\lim_{x \to \frac{1}{2}} (x + 3) = \frac{7}{2}

So, at x=12x = \frac{1}{2}, 12x1 - 2x approaches 0, and x+3x + 3 approaches 72\frac{7}{2}.

4. Behavior Around x=12x = \frac{1}{2}:

  • The next section uses a table to evaluate the sign of 12x1 - 2x as xx approaches 12\frac{1}{2} from both sides:

    • As x12x \to \frac{1}{2}^- (from the left), 12x+01 - 2x \to +0
    • As x12+x \to \frac{1}{2}^+ (from the right), 12x01 - 2x \to -0

    This shows that the function's behavior changes around x=12x = \frac{1}{2}.

5. Final Conclusion:

The final limit for limx12x+312x\lim_{x \to \frac{1}{2}} \frac{x + 3}{1 - 2x} is calculated as follows:

limx12=+\lim_{x \to \frac{1}{2}^-} = +\infty limx12+=\lim_{x \to \frac{1}{2}^+} = -\infty

Hence, the limit does not exist as the function tends to ++\infty from the left and -\infty from the right.


Summary:

  • The limit problem limx12x+312x\lim_{x \to \frac{1}{2}} \frac{x + 3}{1 - 2x} results in a vertical asymptote at x=12x = \frac{1}{2}.
  • The behavior of the function differs as xx approaches 12\frac{1}{2} from the left (positive infinity) and from the right (negative infinity), indicating that the two-sided limit does not exist.

Would you like further details or have specific questions about this? Here are five related questions that might help expand understanding:

  1. How do you determine the behavior of limits when a function approaches infinity?
  2. What happens when both the numerator and denominator tend to 0 in a limit problem?
  3. Can a limit exist if the left-hand and right-hand limits are different?
  4. How do you deal with indeterminate forms like 00\frac{0}{0} in limit problems?
  5. What are vertical asymptotes, and how do they affect limits?

Tip: In problems involving limits where substitution leads to an indeterminate form (like 00\frac{0}{0}), try simplifying the expression or consider using L'Hopital's Rule if applicable.

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Math Problem Analysis

Mathematical Concepts

Limits
Indeterminate Forms
Vertical Asymptotes

Formulas

lim_{x -> 1/2} (x + 3) / (1 - 2x)
lim_{x -> a} f(x) = L

Theorems

Limit Theorem
Behavior of functions around discontinuities

Suitable Grade Level

Grade 11-12 (Advanced High School)