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### Problem 6:
The circle represents the global aluminum production. The production of a country constitutes \( \frac{4}{15} \) of the global production, and this is represented by the shaded sector. We are asked to determine the angle of the shaded sector at the center.

#### Solution:
- The total angle of the circle is \( 360^\circ \).
- The fraction of the circle representing the production is \( \frac{4}{15} \).

To find the angle, we multiply the total angle by this fraction:
\[
\theta = \frac{4}{15} \times 360^\circ = \frac{1440^\circ}{15} = 96^\circ
\]

**Answer for Problem 6**: The angle is \( 96^\circ \).

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### Problem 7:
We are given three negative integers \( x \), \( y \), and \( z \), such that:
\[
\frac{x}{0.3} = \frac{y}{0.5} = \frac{z}{0.45}
\]
We need to determine the order of \( x \), \( y \), and \( z \) in

This set of problems covers a variety of topics, including determining the angle of a fraction of a circle, ordering negative integers by solving ratio equations, and expressing powers and roots in terms of variables. Perfect for students in grades 9-10 learning algebra and geometry.

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