Math Problem Statement

Given PR = 39, find PQ

Solution

To solve the problem, let's analyze the information given in the image step-by-step:

  1. Given Information:

    • PR=39PR = 39
    • We are asked to find PQPQ.
  2. Diagram Analysis:

    • There is a line segment with three points: PP, QQ, and RR.
    • The length from PP to QQ is represented by the expression 9x+79x + 7.
    • The length from QQ to RR is represented by the expression 3x+20-3x + 20.
    • The total length PRPR (from PP to RR) is the sum of PQPQ and QRQR.
  3. Set Up the Equation: Since PR=PQ+QRPR = PQ + QR, we can write: 9x+7+(3x+20)=399x + 7 + (-3x + 20) = 39

  4. Simplify the Equation: Combine like terms: 9x3x+7+20=399x - 3x + 7 + 20 = 39 6x+27=396x + 27 = 39

  5. Solve for xx: Subtract 27 from both sides: 6x=126x = 12 Divide both sides by 6: x=2x = 2

  6. Find PQPQ: Substitute x=2x = 2 back into the expression for PQPQ: PQ=9x+7=9(2)+7=18+7=25PQ = 9x + 7 = 9(2) + 7 = 18 + 7 = 25

Conclusion:

The length of PQPQ is 25.

Would you like more details or have any questions?

Further Related Questions:

  1. How would the solution change if PRPR had a different value?
  2. Can you solve for QRQR using the given information?
  3. What would happen if the expressions for PQPQ or QRQR were nonlinear?
  4. How do you solve similar problems involving unknowns in geometric figures?
  5. What is the method for solving systems of equations derived from geometric diagrams?

Tip:

Always double-check your setup and ensure all expressions correctly represent the problem conditions before solving equations!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Geometric Relations

Formulas

PR = PQ + QR

Theorems

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Suitable Grade Level

Grades 7-9