Math Problem Statement

PQ = 6x + 25 and QR = 16 - 3x; Find PR.

Solution

The problem provided in the image asks you to find PRPR given the following two segments:

  • PQ=6x+25PQ = 6x + 25
  • QR=163xQR = 16 - 3x

Since PP, QQ, and RR are collinear points, we can express PRPR as:

PR=PQ+QRPR = PQ + QR

Let's substitute the values for PQPQ and QRQR:

PR=(6x+25)+(163x)PR = (6x + 25) + (16 - 3x)

Now, we can simplify the expression:

PR=6x+25+163xPR = 6x + 25 + 16 - 3x PR=3x+41PR = 3x + 41

Thus, PR=3x+41PR = 3x + 41.

Would you like me to explain any part of this further, or go into details about solving for xx if more information is provided?

Here are 5 questions related to the topic:

  1. How would you solve for xx if PRPR were given a specific value?
  2. How can you use the concept of collinearity to solve problems involving line segments?
  3. What are the implications if PRPR is negative?
  4. How would you approach finding xx in a system where PQ=QRPQ = QR?
  5. What are some real-world applications of this type of algebraic reasoning?

Tip: Always check the relationships between given segments (like addition of collinear segments) to ensure the equations are set up correctly.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Collinear Points

Formulas

PR = PQ + QR

Theorems

Collinearity Theorem

Suitable Grade Level

Grades 6-8