To solve the equation \( P = 2l + 2w \) for \( l \), follow these steps:

1. Start with the given equation:
   \[
   P = 2l + 2w
   \]

2. Subtract \( 2w \) from both sides to isolate the terms involving \( l \):
   \[
   P - 2w = 2l
   \]

3. Divide both sides by 2 to solve for \( l \):
   \[
   l = \frac{P - 2w}{2}
   \]

So, the equation solved for \( l \) is:
   \[
   l = \frac{P - 2w}{2}
   \]

Would you like more details or have any questions?

Here are 5 related questions to further explore this topic:

1. If \( P = 30 \) and \( w = 5 \), what is the value of \( l \)?
2. How would this formula change if the perimeter were given in terms of a different shape, like a triangle?
3. What is the geometric interpretation of this formula?
4. How would you rearrange the formula to solve for \( w \) instead?
5. How can this equation be applied in a real-world context, such as fencing a rectangular garden?

**Tip:** When solving for a variable, your goal is to isolate that variable on one side of the equation using inverse operations.

Learn how to solve the equation P = 2l + 2w for l with a detailed step-by-step solution. This problem involves key algebraic concepts, such as rearranging linear equations, and covers the formula for the perimeter of a rectangle. Suitable for students in Grades 6-8.

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