The equation provided is:

\[
P = 2L + 2W
\]

You are asked to solve for \( W \).

To solve for \( W \):

1. Subtract \( 2L \) from both sides of the equation to start isolating \( W \):

\[
P - 2L = 2W
\]

2. Next, divide both sides by 2 to solve for \( W \):

\[
W = \frac{P - 2L}{2}
\]

So, the solution for \( W \) is:

\[
W = \frac{P - 2L}{2}
\]

Would you like more details or have any questions?

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Here are 5 related questions you might find useful:
1. How do you solve for \( L \) instead of \( W \) in the same equation?
2. What does the equation \( P = 2L + 2W \) represent in geometry?
3. If \( P \) and \( L \) are known, how can you calculate \( W \) using this formula?
4. How can you derive the formula for the perimeter of a rectangle?
5. What would happen to the formula if \( P \) represented the perimeter of a different shape, like a triangle?

**Tip:** When solving for a variable, aim to move all terms involving that variable to one side of the equation, then factor it out if needed.

Learn how to solve the linear equation P = 2L + 2W for W with a detailed step-by-step solution. This problem covers key algebraic concepts, including solving linear equations and manipulating variables. Suitable for students in Grades 7-9.

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