Math Problem Statement

2-48=(H-48)((5,101-14,930)/5,101) what is H

Solution

We are given the equation:

248=(H48)(5,10114,9305,101)2 - 48 = (H - 48) \left(\frac{5,101 - 14,930}{5,101}\right)

Let's solve for HH.

Step 1: Simplify the expression inside the parentheses.

5,10114,9305,101=9,8295,101\frac{5,101 - 14,930}{5,101} = \frac{-9,829}{5,101}

Now, approximate the division: 9,8295,1011.926\frac{-9,829}{5,101} \approx -1.926

Step 2: Substitute the simplified expression back into the equation:

248=(H48)(1.926)2 - 48 = (H - 48)(-1.926) 46=(H48)(1.926)-46 = (H - 48)(-1.926)

Step 3: Solve for HH.

Divide both sides by 1.926-1.926: 461.926=H48\frac{-46}{-1.926} = H - 48 23.88H4823.88 \approx H - 48

Step 4: Add 48 to both sides to isolate HH:

H23.88+48H \approx 23.88 + 48 H71.88H \approx 71.88

Thus, H71.88H \approx 71.88.


Do you want more details on any step? Let me know if you have any questions!

Related Questions:

  1. What is the exact value if we calculate the decimal more precisely?
  2. How can this be solved graphically?
  3. What happens if we change the denominator to a different value?
  4. How would this be different if the expression was squared?
  5. How can you check if the solution is correct by substituting HH back into the original equation?

Tip: Always double-check your arithmetic operations, especially when dealing with negative values.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Simplifying Expressions

Formulas

Linear equation: ax + b = c
Fraction simplification: (a - b) / a

Theorems

Basic properties of linear equations

Suitable Grade Level

Grades 9-11