Math Problem Statement

y' = x + y

Solution

The given differential equation is:

y=x+yy' = x + y

This is a first-order linear ordinary differential equation. To solve it, we can use the method of integrating factors.

Step 1: Rewrite the equation

The standard form for a linear differential equation is:

y+P(x)y=Q(x)y' + P(x)y = Q(x)

So, we can rewrite the equation as:

yy=xy' - y = x

Here, P(x)=1P(x) = -1 and Q(x)=xQ(x) = x.

Step 2: Find the integrating factor

The integrating factor (IF) is given by:

μ(x)=eP(x)dx\mu(x) = e^{\int P(x) \, dx}

In our case, P(x)=1P(x) = -1, so:

μ(x)=e1dx=ex\mu(x) = e^{\int -1 \, dx} = e^{-x}

Step 3: Multiply through by the integrating factor

Now, multiply both sides of the equation by exe^{-x}:

exyexy=exxe^{-x} y' - e^{-x} y = e^{-x} x

The left side of the equation is now the derivative of exye^{-x} y, using the product rule:

ddx(exy)=exx\frac{d}{dx} \left( e^{-x} y \right) = e^{-x} x

Step 4: Integrate both sides

Now, integrate both sides with respect to xx:

ddx(exy)dx=exxdx\int \frac{d}{dx} \left( e^{-x} y \right) \, dx = \int e^{-x} x \, dx

The left side simplifies to:

exye^{-x} y

To solve the right-hand side, we need to use integration by parts. Let:

  • u=xu = x, so du=dxdu = dx
  • dv=exdxdv = e^{-x} dx, so v=exv = -e^{-x}

Using the integration by parts formula udv=uvvdu\int u \, dv = uv - \int v \, du, we get:

exxdx=xex+exdx=xexex\int e^{-x} x \, dx = -x e^{-x} + \int e^{-x} \, dx = -x e^{-x} - e^{-x}

Step 5: Combine the results

Now, substituting back, we have:

exy=xexex+Ce^{-x} y = -x e^{-x} - e^{-x} + C

where CC is the constant of integration. Multiply through by exe^{x} to solve for yy:

y=x1+Cexy = -x - 1 + C e^{x}

Final Solution:

The general solution to the differential equation is:

y=x1+Cexy = -x - 1 + C e^{x}

Where CC is an arbitrary constant.


Would you like more details or have any questions about the steps? Here's a list of related questions:

  1. How does the method of integrating factors work for non-homogeneous equations?
  2. What are other methods for solving first-order differential equations?
  3. Can this method be extended to second-order differential equations?
  4. What does the constant CC represent in the solution?
  5. How can we solve a differential equation that involves trigonometric functions?

Tip: When solving differential equations, always check if the equation is linear or separable, as this will determine the appropriate method of solution.

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Math Problem Analysis

Mathematical Concepts

First-order differential equations
Linear ordinary differential equations
Integrating factors
Integration by parts

Formulas

y' + P(x)y = Q(x)
μ(x) = e^∫ P(x) dx
∫ u dv = uv - ∫ v du

Theorems

Method of integrating factors
Integration by parts

Suitable Grade Level

Grades 11-12