Math Problem Statement

(E1): 3 - 2e^{x^2 - 1} = 0 over ℝ (E2): ln(1 + e^{-x}) = 3 over ℝ

Solution

It looks like you've shared an image with two equations. Let me interpret them and provide solutions or analysis for both:

  1. Equation (E1): 32ex21=0onR3 - 2e^{x^2 - 1} = 0 \quad \text{on} \, \mathbb{R}

    To solve this equation, we'll first isolate the exponential term and then simplify the equation.

  2. Equation (E2): ln(1+ex)=3onR\ln(1 + e^{-x}) = 3 \quad \text{on} \, \mathbb{R}

    Similarly, we'll isolate the logarithmic term to find the solution.

Let me know if you want to dive into the steps of solving these equations!

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Math Problem Analysis

Mathematical Concepts

Exponential Equations
Logarithmic Equations
Algebra

Formulas

Exponential form: e^x
Logarithmic form: ln(x)
Properties of logarithms and exponentials: ln(e^x) = x

Theorems

Logarithm-Exponential Inverse Property
Basic Algebraic Manipulation

Suitable Grade Level

Grades 11-12