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The given inequality is:

\[
\ln(x^2 - 4e^2) < 1 + \ln(3x)
\]

### Steps to solve the inequality:

1. **Isolate the logarithmic terms**: Subtract \(\ln(3x)\) from both sides to keep all logarithmic expressions on one side:
   \[
   \ln(x^2 - 4e^2) - \ln(3x) < 1
   \]

2. **Use logarithmic properties**: Apply the property \(\ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right)\):
   \[
   \ln\left(\frac{x^2 - 4e^2}{3x}\right) < 1
   \]

3. **Exponentiate both sides**: To eliminate the natural logarithm, apply the exponential function (\(e^{\ln(\cdot)} = \cdot\)) to both sides:
   \[
   \frac{x^2 - 4e^2}{3x} < e^1
   \]
   Simplifying:
   \[
   \frac{x^2 - 4e^2}{3x} < e
   \]

4. **Solve the resulting inequality**: Multiply both sides by \(3x\) (assuming \(x > 0\) to keep \(3x > 0\), since logarithms are only defined for positive arguments):
   \[
   x^2 - 4e^2 < 3xe
   \]

5. **Rearrange terms**: Move all terms to one side of the inequality:
   \[
   x^2 - 3xe - 4e^2 < 0
   \]

6. **Solve the quadratic inequality**: Treat this as a quadratic in \(x\):
   \[
   x^2 - 3xe - 4e^2 = 0
   \]
   Solve the quadratic equation using the quadratic formula:
   \[
   x = \frac{-(-3e) \pm \sqrt{(-3e)^2 - 4(1)(-4e^2)}}{2(1)}
   \]
   Simplifying:
   \[
   x = \frac{3e \pm \sqrt{9e^2 + 16e^2}}{2}
   \]
   \[
   x = \frac{3e \pm \sqrt{25e^2}}{2}
   \]
   \[
   x = \frac{3e \pm 5e}{2}
   \]

   The two solutions are:
   \[
   x_1 = \frac{3e + 5e}{2} = 4e, \quad x_2 = \frac{3e - 5e}{2} = -e
   \]

7. **Determine the solution interval**: The quadratic inequality \(x^2 - 3xe - 4e^2 < 0\) is satisfied between the roots \(x = -e\) and \(x = 4e\). However, we must also consider the domain of the original logarithmic expressions:
   - \(x^2 - 4e^2 > 0 \implies x > 2e\) or \(x < -2e\)
   - \(3x > 0 \implies x > 0\)

   Combining these conditions, the solution must be \(2e < x < 4e\).

### Final Answer:
The solution to the inequality is:

\[
2e < x < 4e
\]

Would you like a more detailed explanation or further clarifications?

Here are 5 related questions:
1. How do you solve other inequalities involving logarithms?
2. What happens if the quadratic discriminant is negative?
3. Can logarithmic inequalities have complex number solutions?
4. How do logarithmic properties help in simplifying equations?
5. What is the domain of natural logarithms?

**Tip**: Always check the domain of logarithmic functions to avoid undefined values in the final solution.

Help me solve this problem: ln(x^2 - 4e^2) < 1 + ln(3x)

This page provides a detailed solution to the logarithmic inequality ln(x^2 - 4e^2) < 1 + ln(3x). It involves using properties of logarithms and solving quadratic equations. Suitable for advanced high school students (Grades 11-12).

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