Math Problem Statement

What is the justification for step 2 in the solution process?\begin{array} {rcrclC40C40C40C40C40}&&\frac{1}{2}r:+:\frac{1}{2}&=&\textrm{-}\frac{2}{7}r:+:\frac{6}{7}:-:5\ \textrm{Step 1}&:&\frac{1}{2}r:+:\frac{1}{2}&=&\textrm{-}\frac{2}{7}r:-:\frac{29}{7}\ \textrm{Step 2}&:&\frac{1}{2}r&=&\textrm{-}\frac{2}{7}r:-:\frac{65}{14} \end{array}

Solution

The justification for Step 2 in the solution process involves isolating the term with the variable rr on the left-hand side of the equation by eliminating the constant term on the left-hand side.

Here's how it works:

  1. Starting from Step 1: 12r+12=27r297\frac{1}{2}r + \frac{1}{2} = -\frac{2}{7}r - \frac{29}{7}

  2. Subtract 12\frac{1}{2} from both sides: To eliminate the constant term 12\frac{1}{2} on the left-hand side, subtract 12\frac{1}{2} from both sides of the equation: 12r+1212=27r29712\frac{1}{2}r + \frac{1}{2} - \frac{1}{2} = -\frac{2}{7}r - \frac{29}{7} - \frac{1}{2} Simplifying this gives: 12r=27r(297+12)\frac{1}{2}r = -\frac{2}{7}r - \left(\frac{29}{7} + \frac{1}{2}\right)

  3. Combine the constants on the right-hand side: The right-hand side now involves adding 297\frac{29}{7} and 12\frac{1}{2} as follows: 29712=5814714=6514-\frac{29}{7} - \frac{1}{2} = -\frac{58}{14} - \frac{7}{14} = -\frac{65}{14} So the equation becomes: 12r=27r6514\frac{1}{2}r = -\frac{2}{7}r - \frac{65}{14}

This is Step 2 in the solution process. The key justification for Step 2 is subtracting 12\frac{1}{2} from both sides to isolate the term containing rr on the left side.

Would you like more details or have any further questions?

Related Questions:

  1. How do you combine fractions with different denominators?
  2. What is the next step after isolating the variable terms on each side?
  3. How do you solve equations with variables on both sides?
  4. What does it mean to isolate a variable in an equation?
  5. How do you simplify complex fractions?

Tip: Always check that the fractions are simplified before combining them.

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Math Problem Analysis

Mathematical Concepts

Equations
Fractions

Formulas

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Theorems

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Suitable Grade Level

Grades 9-12