The equation you've provided seems to have some formatting issues. Let's clarify it and solve it.

### Interpretation of the equation:

It seems you have two equations here:
1. \( 3z = 25 \)
2. \( 25 = 49 - z - 6 \)

Let's solve these equations step by step.

### 1. Solving \( 3z = 25 \):

To solve for \( z \):
\[
z = \frac{25}{3} \approx 8.33
\]

### 2. Solving \( 25 = 49 - z - 6 \):

First, simplify the right-hand side:
\[
25 = 43 - z
\]

Now, solve for \( z \):
\[
z = 43 - 25 = 18
\]

### Final Analysis:

These two values of \( z \) don't match, which indicates either a contradiction or that we are dealing with two separate equations. If this was intended to be one combined equation, it would be inconsistent.

Would you like to clarify the equation, or have any questions? 

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2. What are the solutions for the quadratic equation \( x^2 + 5x + 6 = 0 \)?
3. How can you solve a system of linear equations like \( 2x + y = 10 \) and \( 3x - y = 5 \)?
4. What is the process for simplifying \( 2(3x + 4) - 5(x - 2) \)?
5. How can you factorize \( z^2 - 10z + 25 \)?

**Tip:** Always check if equations are correctly formatted before solving to avoid confusion or errors.

Learn how to solve the equations 3z = 25 and 25 = 49 - z - 6 step-by-step with detailed explanations. This problem involves linear equations and equation simplification in algebra. Suitable for students in Grades 7-9.

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