To solve the equation \( 42 = -7(z - 3) \), follow these steps:

1. **Distribute the \(-7\)** on the right-hand side:
   \[
   42 = -7z + 21
   \]

2. **Subtract 21** from both sides of the equation to isolate the term with \(z\):
   \[
   42 - 21 = -7z
   \]
   \[
   21 = -7z
   \]

3. **Divide both sides** of the equation by \(-7\) to solve for \(z\):
   \[
   z = \frac{21}{-7}
   \]
   \[
   z = -3
   \]

So, the solution is \( z = -3 \).

Would you like a detailed explanation, or do you have any questions?

Here are 5 related questions:
1. Solve for \( x \): \( 36 = -9(x - 4) \).
2. Solve for \( y \): \( 56 = 8(y + 5) \).
3. Solve for \( a \): \( -14 = -7(a - 6) \).
4. Solve for \( b \): \( 90 = -10(b + 3) \).
5. Solve for \( c \): \( -35 = 5(2c - 1) \).

**Tip**: Always distribute constants before isolating the variable when solving linear equations.

Learn how to solve the linear equation 42 = -7(z - 3) step-by-step with detailed explanations. This problem involves basic algebraic concepts, including linear equations and the distributive property. Suitable for students in Grades 6-8.

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