It looks like the image you've uploaded contains a question related to finding complex values using De Moivre's Theorem. The task appears to involve calculating the complex roots of a given number, specifically $z = (3 + \sqrt{2} + 3i)^{1/3}$, by obtaining the polar form and using the general argument.

In order to solve this, we need to follow the steps outlined:

1. Convert to Polar Form: The first part asks for expressing the complex number in polar form $r (\cos \theta + i \sin \theta)$, where $r$ is the modulus and $\theta$ is the argument (angle).

   • To find $r$, calculate the modulus: $r = \sqrt{x^2 + y^2}$ where $x$ and $y$ are the real and imaginary parts, respectively.

   • To find the argument $\theta$, use the formula: $\theta = \arg(z) = \tan^{-1}\left(\frac{y}{x}\right)$

2. Apply De Moivre's Theorem: De Moivre's Theorem states that for a complex number in polar form: $\left[ r (\cos \theta + i \sin \theta) \right]^n = r^n (\cos(n\theta) + i \sin(n\theta))$ For the cube roots, we set $n = \frac{1}{3}$ and calculate the three roots by varying $k = 0, 1, 2$.

Do you want me to walk you through each step of the calculation for the problem presented in the image? Let me know if you'd like further details!