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The extracted text from the image is partially unclear, but it appears to be:

\[ \text{Nilai} \  ^2\log 125 \cdot  ^5\log 9 \cdot  ^3\log \frac{1}{16} = \dots \]

It involves logarithmic expressions with different bases. Let's solve this systematically:

### Step 1: Simplifying each logarithmic term

1. \( ^2\log 125 \): 
   This means the logarithm of 125 to the base 2. We can express 125 as \( 5^3 \), so:
   \[
   ^2\log 125 = \frac{3 \log 5}{\log 2}
   \]

2. \( ^5\log 9 \): 
   This means the logarithm of 9 to the base 5. We can express 9 as \( 3^2 \), so:
   \[
   ^5\log 9 = \frac{2 \log 3}{\log 5}
   \]

3. \( ^3\log \frac{1}{16} \): 
   The logarithm of \( \frac{1}{16} \) to the base 3. Since \( 16 = 2^4 \), and taking the logarithm:
   \[
   ^3\log \frac{1}{16} = \frac{-4 \log 2}{\log 3}
   \]

### Step 2: Combine the results

Now, multiplying the three logarithms:
\[
\left( \frac{3 \log 5}{\log 2} \right) \cdot \left( \frac{2 \log 3}{\log 5} \right) \cdot \left( \frac{-4 \log 2}{\log 3} \right)
\]

This simplifies as:
\[
3 \cdot 2 \cdot (-4) = -24
\]

Therefore, the value of the expression is \( -24 \).

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Would you like any further details on the solution, or have any questions?

Here are 5 related questions you can explore:
1. How do you convert logarithms between different bases?
2. What is the change of base formula for logarithms?
3. How can logarithmic properties simplify complex expressions?
4. How do you handle negative values in logarithmic equations?
5. What real-world applications rely on logarithmic calculations?

**Tip**: When simplifying logarithmic expressions, converting terms to a common base often helps to reduce the complexity of the problem.

Calculate the value of 2^log 125 * 5^log 9 * 3^log 1/16.

Explore how to solve complex logarithmic expressions like 2^log 125 * 5^log 9 * 3^log 1/16. This guide provides step-by-step calculations using the change of base formula and properties of logarithms, suitable for high school students.

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