You have three logarithmic expressions:

1. \( 3 \log 125 \)
2. \( 5 \log 8 \)
3. \( 2 \log 9 \)

Let's simplify each one individually:

### 1. \( 3 \log 125 \)
Using the logarithmic property \( a \log b = \log b^a \), we rewrite it as:
\[
3 \log 125 = \log 125^3 = \log 1953125
\]

### 2. \( 5 \log 8 \)
Again, applying \( a \log b = \log b^a \), we get:
\[
5 \log 8 = \log 8^5 = \log 32768
\]

### 3. \( 2 \log 9 \)
Using the same property:
\[
2 \log 9 = \log 9^2 = \log 81
\]

The final simplified expressions are:
\[
3 \log 125 = \log 1953125
\]
\[
5 \log 8 = \log 32768
\]
\[
2 \log 9 = \log 81
\]

Would you like to know more details or have any questions about logarithms or simplification?

Here are 5 related questions:
1. What is the logarithmic property \( \log(a \cdot b) \)?
2. How would you simplify \( 4 \log 16 \)?
3. What is the value of \( \log 10 \) in base 10?
4. How do you convert natural logarithms to base 10?
5. How can logarithms be used to solve exponential equations?

**Tip:** Always remember the power rule of logarithms: \( a \log b = \log b^a \).

Learn how to simplify logarithmic expressions such as 3 log 125, 5 log 8, and 2 log 9 using the power rule of logarithms. This step-by-step solution covers key concepts in algebra and logarithmic properties, suitable for students in Grades 9-12.

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