You have three logarithmic expressions:

1. $3 \log 125$
2. $5 \log 8$
3. $2 \log 9$

Let's simplify each one individually:

1. $3 \log 125$

Using the logarithmic property $a \log b = \log b^a$, we rewrite it as: $3 \log 125 = \log 125^3 = \log 1953125$

2. $5 \log 8$

Again, applying $a \log b = \log b^a$, we get: $5 \log 8 = \log 8^5 = \log 32768$

3. $2 \log 9$

Using the same property: $2 \log 9 = \log 9^2 = \log 81$

The final simplified expressions are: $3 \log 125 = \log 1953125$ $5 \log 8 = \log 32768$ $2 \log 9 = \log 81$

Would you like to know more details or have any questions about logarithms or simplification?

Here are 5 related questions:

1. What is the logarithmic property $\log(a \cdot b)$?
2. How would you simplify $4 \log 16$?
3. What is the value of $\log 10$ in base 10?
4. How do you convert natural logarithms to base 10?
5. How can logarithms be used to solve exponential equations?

Tip: Always remember the power rule of logarithms: $a \log b = \log b^a$.