Math Problem Statement

1+z1z=2\imaginaryI\frac{1+z}{1-z}=2-\imaginaryI

Solution

We are tasked with solving the equation:

1+z1z=2i\frac{1+z}{1-z} = 2 - i

Let's solve this step by step.

Step 1: Multiply both sides of the equation by 1z1 - z to eliminate the denominator on the left-hand side:

1+z=(2i)(1z)1 + z = (2 - i)(1 - z)

Step 2: Expand the right-hand side of the equation:

1+z=(2i)(1z)1 + z = (2 - i)(1 - z) =2(1z)i(1z)= 2(1 - z) - i(1 - z) =22zi+iz= 2 - 2z - i + iz So the equation becomes: 1+z=22zi+iz1 + z = 2 - 2z - i + iz

Step 3: Rearrange the terms so that all terms involving zz are on one side and constant terms are on the other side:

1+z=2i2z+iz1 + z = 2 - i - 2z + iz Now move all the terms involving zz to one side: 1+z+2ziz=2i1 + z + 2z - iz = 2 - i Combine like terms: 1+3ziz=2i1 + 3z - iz = 2 - i Now, move the constants to the other side: 3ziz=2i13z - iz = 2 - i - 1 Simplify the right-hand side: 3ziz=1i3z - iz = 1 - i

Step 4: Factor out zz on the left-hand side:

z(3i)=1iz(3 - i) = 1 - i

Step 5: Solve for zz:

z=1i3iz = \frac{1 - i}{3 - i}

To simplify this complex fraction, we multiply both the numerator and denominator by the complex conjugate of the denominator, which is 3+i3 + i:

z=(1i)(3+i)(3i)(3+i)z = \frac{(1 - i)(3 + i)}{(3 - i)(3 + i)}

Step 6: Simplify the denominator:

The denominator is a difference of squares: (3i)(3+i)=32i2=9(1)=9+1=10(3 - i)(3 + i) = 3^2 - i^2 = 9 - (-1) = 9 + 1 = 10

Step 7: Simplify the numerator:

Expand (1i)(3+i)(1 - i)(3 + i): (1i)(3+i)=1(3+i)i(3+i)(1 - i)(3 + i) = 1(3 + i) - i(3 + i) =3+i3ii2=3+i3i+1=42i= 3 + i - 3i - i^2 = 3 + i - 3i + 1 = 4 - 2i

Thus, we have: z=42i10z = \frac{4 - 2i}{10}

Step 8: Final result:

z=4102i10=25i5z = \frac{4}{10} - \frac{2i}{10} = \frac{2}{5} - \frac{i}{5}

Therefore, the solution to the equation is: z=25i5z = \frac{2}{5} - \frac{i}{5}


Would you like a more detailed explanation of any step, or do you have additional questions on complex numbers?

Here are some related questions to explore further:

  1. How do you simplify a complex fraction like 1i3i\frac{1 - i}{3 - i}?
  2. What are the real and imaginary parts of a complex number?
  3. How do you multiply and divide complex numbers?
  4. What is the geometric interpretation of a complex number?
  5. How do you convert a complex number to polar form?

Tip: When dividing complex numbers, multiplying by the conjugate of the denominator is a key technique to rationalize the denominator.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Algebra
Equations

Formulas

Complex number division and multiplication by the conjugate
Algebraic equation solving

Theorems

Conjugate of a complex number
Multiplying complex numbers

Suitable Grade Level

Grades 11-12