Math Problem Statement

  1. 2x + 11 2. (2z + y) -5 3. |(y + z) - x| x is 11 y is 0 z is 22

Solution

Let's solve each expression using the values x=11x = 11, y=0y = 0, and z=22z = 22.

  1. For 2x+112x + 11: 2(11)+11=22+11=332(11) + 11 = 22 + 11 = 33

  2. For (2z+y)5(2z + y) - 5: (2(22)+0)5=(44+0)5=445=39(2(22) + 0) - 5 = (44 + 0) - 5 = 44 - 5 = 39

  3. For (y+z)x|(y + z) - x|: (0+22)11=2211=11=11|(0 + 22) - 11| = |22 - 11| = |11| = 11

Summary of Results:

  1. 2x+11=332x + 11 = 33
  2. (2z+y)5=39(2z + y) - 5 = 39
  3. (y+z)x=11|(y + z) - x| = 11

Would you like any further details or explanations? Here are some related questions:

  1. How do you simplify expressions with absolute values?
  2. What are some common applications of linear equations?
  3. Can you explain the significance of variable substitution in algebra?
  4. What are the properties of absolute values?
  5. How would these calculations change if the values of xx, yy, and zz were different?

Tip: Always double-check your values before substituting them into equations to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Absolute Values

Formulas

2x + 11
(2z + y) - 5
|(y + z) - x|

Theorems

Properties of Absolute Values
Linear Equation Properties

Suitable Grade Level

Grades 7-9