Math Problem Statement

  1. 2x + 11 2. (2z + y) - 5 3. |(y + z) - x| x is 0 y is 22 z is 20

Solution

Let's evaluate each of these expressions step-by-step, given that x=0x = 0, y=22y = 22, and z=20z = 20.

1. 2x+112x + 11

Substitute x=0x = 0: 20+11=0+11=112 \cdot 0 + 11 = 0 + 11 = 11 Answer: 2x+11=112x + 11 = 11

2. (2z+y)5(2z + y) - 5

Substitute z=20z = 20 and y=22y = 22: (220+22)5=(40+22)5=625=57(2 \cdot 20 + 22) - 5 = (40 + 22) - 5 = 62 - 5 = 57 Answer: (2z+y)5=57(2z + y) - 5 = 57

3. (y+z)x|(y + z) - x|

Substitute y=22y = 22, z=20z = 20, and x=0x = 0: (22+20)0=420=42=42|(22 + 20) - 0| = |42 - 0| = |42| = 42 Answer: (y+z)x=42|(y + z) - x| = 42

Summary of Results

  1. 2x+11=112x + 11 = 11
  2. (2z+y)5=57(2z + y) - 5 = 57
  3. (y+z)x=42|(y + z) - x| = 42

Would you like further details on any of these calculations?


Here are five related questions:

  1. What is the value of 2x+3y2x + 3y given the same values for xx, yy, and zz?
  2. How does the expression 3zy+73z - y + 7 evaluate for x=0x = 0, y=22y = 22, and z=20z = 20?
  3. Can you calculate yx+zy|y - x| + |z - y| with these values?
  4. What is the outcome of x+y+zx + y + z when x=0x = 0, y=22y = 22, and z=20z = 20?
  5. How would you simplify x+yz|x + y - z| using the provided values?

Tip: When solving expressions with absolute values, remember that the absolute value function, a|a|, removes any negative signs, making a|a| always non-negative.

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Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value
Linear Expressions

Formulas

Linear equation: ax + b
Absolute value: |a|

Theorems

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Suitable Grade Level

Grades 6-8