Math Problem Statement

if x=1 y=1 and z=0 what are the answer to there problems ? 1. 2x + 11 2. (2z+y) -5 3.|(Y+z)-X|

Solution

Let's solve the given problems step by step, given that:

  • x=1x = 1
  • y=1y = 1
  • z=0z = 0

1. 2x+112x + 11

Substitute x=1x = 1: 2(1)+11=2+11=132(1) + 11 = 2 + 11 = 13 Answer: 13

2. (2z+y)5(2z + y) - 5

Substitute z=0z = 0 and y=1y = 1: (2(0)+1)5=(0+1)5=15=4(2(0) + 1) - 5 = (0 + 1) - 5 = 1 - 5 = -4 Answer: -4

3. (y+z)x|(y + z) - x|

Substitute y=1y = 1, z=0z = 0, and x=1x = 1: (1+0)1=11=0=0| (1 + 0) - 1 | = | 1 - 1 | = | 0 | = 0 Answer: 0

Summary of Answers:

  1. 2x+11=132x + 11 = 13
  2. (2z+y)5=4(2z + y) - 5 = -4
  3. (y+z)x=0|(y + z) - x| = 0

Would you like more details or have any questions on this?

Here are 5 related questions

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Basic Algebra
Substitution
Absolute Value

Formulas

2x + 11
(2z + y) - 5
|(y + z) - x|

Theorems

Properties of absolute value
Basic algebraic manipulation

Suitable Grade Level

Grades 5-7