Math Problem Statement

Math problems involving absolute value equations and expressions.

Solution

Let's go through the problems one by one and solve them:

Exercises 1-4: Simplify the expression.

  1. 2|-2|

    • The absolute value of 2-2 is 22.
    • Answer: 22
  2. 77|-7| - |7|

    • 7=7|-7| = 7 and 7=7|7| = 7, so 77=07 - 7 = 0.
    • Answer: 00
  3. 3+2|-3 + 2|

    • First, simplify inside the absolute value: 3+2=1-3 + 2 = -1.
    • 1=1|-1| = 1.
    • Answer: 11
  4. 155-\frac{-15}{5}

    • Simplify the fraction first: 155=3\frac{-15}{5} = -3.
    • The negative sign outside makes it (3)=3-(-3) = 3.
    • Answer: 33

Exercises 5-8: Solve the equation and graph the solutions if possible.

  1. r=5|r| = 5

    • This gives two solutions: r=5r = 5 or r=5r = -5.
    • Graph: Mark points at r=5r = 5 and r=5r = -5 on the number line.
  2. q=7|q| = -7

    • Since absolute values cannot be negative, there is no solution.
  3. b2=5|b - 2| = 5

    • This gives two cases:
      1. b2=5b - 2 = 5, so b=7b = 7.
      2. b2=5b - 2 = -5, so b=3b = -3.
    • Graph: Mark points at b=7b = 7 and b=3b = -3 on the number line.
  4. k+6=9|k + 6| = 9

    • This gives two cases:
      1. k+6=9k + 6 = 9, so k=3k = 3.
      2. k+6=9k + 6 = -9, so k=15k = -15.
    • Graph: Mark points at k=3k = 3 and k=15k = -15 on the number line.

Exercises 9-14: Solve the equation and check the solutions.

  1. 5p=35|-5p| = 35

    • Solve for pp: 5p=35|-5p| = 35 gives two cases:
      1. 5p=35-5p = 35, so p=7p = -7.
      2. 5p=35-5p = -35, so p=7p = 7.
    • Answer: p=7p = -7 or p=7p = 7.
  2. a3=4\left| \frac{a}{3} \right| = 4

    • Solve for aa: a3=4\left| \frac{a}{3} \right| = 4 gives two cases:
      1. a3=4\frac{a}{3} = 4, so a=12a = 12.
      2. a3=4\frac{a}{3} = -4, so a=12a = -12.
    • Answer: a=12a = 12 or a=12a = -12.
  3. 8y3=13|8y - 3| = 13

    • Solve for yy: 8y3=13|8y - 3| = 13 gives two cases:
      1. 8y3=138y - 3 = 13, so 8y=168y = 16, and y=2y = 2.
      2. 8y3=138y - 3 = -13, so 8y=108y = -10, and y=54y = -\frac{5}{4}.
    • Answer: y=2y = 2 or y=54y = -\frac{5}{4}.

Would you like more details on any specific problem or topic?

Here are some related questions:

  1. How do you determine whether an absolute value equation has no solution?
  2. What happens when you take the absolute value of a positive or negative number?
  3. How do you solve compound absolute value inequalities?
  4. What are the steps to graphing absolute value equations?
  5. How do you handle absolute values in equations involving variables?

Tip: Always isolate the absolute value term first before considering the two possible cases when solving absolute value equations.

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Math Problem Analysis

Mathematical Concepts

Absolute Value
Algebra
Equations

Formulas

|x| = a
Solving for variables in absolute value equations

Theorems

Absolute value properties
Basic equation solving

Suitable Grade Level

Grades 6-8