Math Problem Statement

De la siguiente figura: a) Calcule el valor de x. b) Use el gráfico para calcular E = tan(θ) + √5 · sec(θ).

Solution

Let's analyze the given problem step by step:


Part (a): Calculate the value of xx

The triangle is a right triangle, with the hypotenuse being ACAC and one leg as AB=4AB = 4. The horizontal leg BCBC has a total length of x+5x + 5, where the segment ABAB starts from x1x - 1.

Using the Pythagorean theorem for the triangle: AB2+BC2=AC2AB^2 + BC^2 = AC^2

  1. AB=4AB = 4 (vertical side)
  2. BC=(x1)+(x+5)=2x+4BC = (x - 1) + (x + 5) = 2x + 4
  3. AC=x+5AC = x + 5

Substitute these values: 42+(2x+4)2=(x+5)24^2 + (2x + 4)^2 = (x + 5)^2

Simplify: 16+(2x+4)2=(x+5)216 + (2x + 4)^2 = (x + 5)^2

Expand both sides: 16+4x2+16x+16=x2+10x+2516 + 4x^2 + 16x + 16 = x^2 + 10x + 25

Simplify further: 4x2+16x+32=x2+10x+254x^2 + 16x + 32 = x^2 + 10x + 25

Rearrange all terms: 4x2x2+16x10x+3225=04x^2 - x^2 + 16x - 10x + 32 - 25 = 0

3x2+6x+7=03x^2 + 6x + 7 = 0

Solve the quadratic equation using the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Here:

  • a=3a = 3
  • b=6b = 6
  • c=7c = 7

Substitute: x=6±624(3)(7)2(3)x = \frac{-6 \pm \sqrt{6^2 - 4(3)(7)}}{2(3)}

Simplify: x=6±36846x = \frac{-6 \pm \sqrt{36 - 84}}{6}

x=6±486x = \frac{-6 \pm \sqrt{-48}}{6}

The discriminant is negative, which means there is no real solution for xx. It appears there may be an inconsistency in the diagram or question setup.


Part (b): Calculate E=tanθ+5secθE = \tan\theta + \sqrt{5} \cdot \sec\theta

If we assume the triangle dimensions resolve to valid values of θ\theta, then:

  1. Define trigonometric ratios:

    • tanθ=oppositeadjacent=4x1\tan\theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{4}{x - 1}
    • secθ=hypotenuseadjacent=x+5x1\sec\theta = \frac{\text{hypotenuse}}{\text{adjacent}} = \frac{x + 5}{x - 1}
  2. Substitute these into EE: E=tanθ+5secθE = \tan\theta + \sqrt{5} \cdot \sec\theta

    E=4x1+5x+5x1E = \frac{4}{x - 1} + \sqrt{5} \cdot \frac{x + 5}{x - 1}

    Combine into a single fraction: E=4+5(x+5)x1E = \frac{4 + \sqrt{5}(x + 5)}{x - 1}

    Simplify further: E=4+5x+55x1E = \frac{4 + \sqrt{5}x + 5\sqrt{5}}{x - 1}

To calculate a numerical value for EE, a valid xx is needed, which was not determined due to the inconsistency in part (a).


Would you like me to revisit part (a), explore alternative solutions, or clarify further? Let me know! Here are five follow-up questions for you:

  1. Do you want me to recheck the equation derived in part (a)?
  2. Should I explain how to handle the negative discriminant for xx?
  3. Would you like me to further elaborate on the trigonometric relationships in part (b)?
  4. Do you want me to plot the functions to visualize their behavior?
  5. Should I help simplify EE further for theoretical analysis?

Tip: Always verify the dimensions and relationships in diagrams carefully to ensure consistent problem-solving!

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Math Problem Analysis

Mathematical Concepts

Algebra
Trigonometry
Quadratic Equations
Pythagorean Theorem

Formulas

Pythagorean theorem: a^2 + b^2 = c^2
Trigonometric identities: tan(θ) = opposite/adjacent, sec(θ) = hypotenuse/adjacent
Quadratic equation formula: x = (-b ± √(b^2 - 4ac)) / 2a

Theorems

Pythagorean Theorem
Quadratic Formula

Suitable Grade Level

Grades 9-12