Math Problem Statement

Find an angle theta, 0 less than or equal too theta less than 2 pi , such that the sum of the squares of sine and cosine of theta is equal to twice the product of the sine and cosine of theta

Solution

We are given the equation:

sin2(θ)+cos2(θ)=2sin(θ)cos(θ)\sin^2(\theta) + \cos^2(\theta) = 2\sin(\theta)\cos(\theta)

Step 1: Use the Pythagorean identity

We know from the Pythagorean identity that:

sin2(θ)+cos2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1

Substitute this into the equation:

1=2sin(θ)cos(θ)1 = 2\sin(\theta)\cos(\theta)

Step 2: Simplify the equation

Now, divide both sides by 2:

12=sin(θ)cos(θ)\frac{1}{2} = \sin(\theta)\cos(\theta)

Step 3: Express the right-hand side using a trigonometric identity

Recall the double-angle identity for sine:

sin(2θ)=2sin(θ)cos(θ)\sin(2\theta) = 2\sin(\theta)\cos(\theta)

So the equation becomes:

12=12sin(2θ)\frac{1}{2} = \frac{1}{2} \sin(2\theta)

Step 4: Solve for θ\theta

Now, multiply both sides by 2 to simplify:

1=sin(2θ)1 = \sin(2\theta)

Thus, we have:

sin(2θ)=1\sin(2\theta) = 1

Step 5: Solve for θ\theta

We know that sin(α)=1\sin(\alpha) = 1 at α=π2+2kπ\alpha = \frac{\pi}{2} + 2k\pi for any integer kk. Therefore, we have:

2θ=π2+2kπ2\theta = \frac{\pi}{2} + 2k\pi

Step 6: Solve for θ\theta

Now, divide both sides by 2:

θ=π4+kπ\theta = \frac{\pi}{4} + k\pi

Step 7: Find the values of θ\theta in the interval [0,2π)[0, 2\pi)

We are asked to find θ\theta such that 0θ<2π0 \leq \theta < 2\pi. Let's consider possible values of kk:

  • For k=0k = 0, θ=π4\theta = \frac{\pi}{4}
  • For k=1k = 1, θ=π4+π=5π4\theta = \frac{\pi}{4} + \pi = \frac{5\pi}{4}

Thus, the two values of θ\theta in the interval [0,2π)[0, 2\pi) are:

θ=π4andθ=5π4\theta = \frac{\pi}{4} \quad \text{and} \quad \theta = \frac{5\pi}{4}

Final Answer:

The angles θ\theta that satisfy the given equation are:

π4 and 5π4\boxed{\frac{\pi}{4} \text{ and } \frac{5\pi}{4}}


Would you like further explanation on any step? Here are some related questions to explore:

  1. Derive the double-angle identity for sine and cosine.
  2. How can you solve trigonometric equations with identities?
  3. What are the other trigonometric identities that can simplify expressions like this?
  4. How do you find the general solution for a sine equation like sin(x)=a\sin(x) = a?
  5. What is the significance of the unit circle in solving trigonometric equations?

Tip: Always try to simplify trigonometric equations using identities before solving for the variable to reduce complexity.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Pythagorean Identity
Double-Angle Identity
Sine and Cosine Functions

Formulas

sin^2(θ) + cos^2(θ) = 1
sin(2θ) = 2sin(θ)cos(θ)
sin(α) = 1 at α = π/2 + 2kπ

Theorems

Pythagorean Identity
Double-Angle Identity for Sine

Suitable Grade Level

Grades 9-12