Math Problem Statement

Answer

The value of ϕ(ϕ(30)).

Solution

The expression given is ϕ(ϕ(30))\phi(\phi(30)), where ϕ\phi denotes the Euler's Totient function. The Totient function ϕ(n)\phi(n) is defined as the number of positive integers up to nn that are coprime to nn.

  1. Calculate ϕ(30)\phi(30):

    • 30=2×3×530 = 2 \times 3 \times 5, so using the formula for the Totient function: ϕ(30)=30(112)(113)(115)\phi(30) = 30 \left(1 - \frac{1}{2}\right)\left(1 - \frac{1}{3}\right)\left(1 - \frac{1}{5}\right) =30×12×23×45=30×830=8= 30 \times \frac{1}{2} \times \frac{2}{3} \times \frac{4}{5} = 30 \times \frac{8}{30} = 8 So, ϕ(30)=8\phi(30) = 8.
  2. Calculate ϕ(8)\phi(8):

    • 8=238 = 2^3, so: ϕ(8)=8(112)=8×12=4\phi(8) = 8 \left(1 - \frac{1}{2}\right) = 8 \times \frac{1}{2} = 4 Therefore, ϕ(ϕ(30))=ϕ(8)=4\phi(\phi(30)) = \phi(8) = 4.

The correct answer is (a) 4.

Would you like more details or have any questions?

Here are some related questions:

  1. How does Euler's Totient function work for composite numbers with multiple prime factors?
  2. What is the Totient function value for other small numbers like 12 or 15?
  3. How does the Totient function apply in cryptography?
  4. Can Euler's Totient function be used in modular arithmetic?
  5. How is the Totient function related to prime numbers?

Tip: Understanding the Totient function helps in number theory, especially in fields like cryptography.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Euler's Totient Function

Formulas

ϕ(n) = n * (1 - 1/p1) * (1 - 1/p2) * ... * (1 - 1/pk), where p1, p2, ..., pk are the distinct prime factors of n

Theorems

Euler's Totient Theorem

Suitable Grade Level

Undergraduate Level or Advanced High School