Math Problem Statement

solve this by finding all solutions and the 6 closest to 0: tan^3 x + tan ^3 x - 3tanx = 3. The answers must come out to the following. All solutions: x=3pi/4+n; x=pi/3+n; Six closest to 0: [-2pi/3,-pi/3,-pi/4,pi/3,2pi/3,3pi/4]

Solution

To solve the equation tan3(x)+tan3(x)3tan(x)=3\tan^3(x) + \tan^3(x) - 3\tan(x) = 3, let's go through the steps carefully.

Step 1: Simplify the equation

The equation is: 2tan3(x)3tan(x)=32\tan^3(x) - 3\tan(x) = 3 Let u=tan(x)u = \tan(x). Then the equation becomes: 2u33u=32u^3 - 3u = 3 Rearrange this to: 2u33u3=02u^3 - 3u - 3 = 0

Step 2: Solve for uu

This is a cubic equation in uu. To find the solutions, we can try to factor or use trial and error to identify possible roots.

Trying u=1u = 1:

2(1)33(1)3=233=402(1)^3 - 3(1) - 3 = 2 - 3 - 3 = -4 \neq 0

Trying u=1u = -1:

2(1)33(1)3=2+33=202(-1)^3 - 3(-1) - 3 = -2 + 3 - 3 = -2 \neq 0

Trying u=3u = 3:

2(3)33(3)3=22793=5493=4202(3)^3 - 3(3) - 3 = 2 \cdot 27 - 9 - 3 = 54 - 9 - 3 = 42 \neq 0

Let's try using other methods like synthetic division or the Rational Root Theorem to identify possible roots, and

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Cubic Equations
Tangent Function

Formulas

tan^3(x) + tan^3(x) - 3tan(x) = 3
2tan^3(x) - 3tan(x) = 3

Theorems

Roots of Trigonometric Equations
Cubic Equation Solution Methods

Suitable Grade Level

Grades 11-12