Here's a system of equations for you to solve:

$2x + 3y = 12$

$4x - y = 5$

Solution:

1. Solve for $y$ in terms of $x$ using the second equation:
   $y = 4x - 5$

2. Substitute this into the first equation:
   $2x + 3(4x - 5) = 12$

3. Expand:
   $2x + 12x - 15 = 12$

4. Simplify:
   $14x = 27$

5. Solve for $x$:
   $x = \frac{27}{14}$

6. Substitute $x = \frac{27}{14}$ into $y = 4x - 5$:
   $y = 4\left(\frac{27}{14}\right) - 5$

   $y = \frac{108}{14} - \frac{70}{14}$

   $y = \frac{38}{14} = \frac{19}{7}$

Final Answer:

$\left( \frac{27}{14}, \frac{19}{7} \right)$

---

Would you like a different type of system (e.g., nonlinear or three-variable)?

Related Questions:

1. Can you solve a nonlinear system of equations?
2. What is the determinant method (Cramer's Rule) for solving systems?
3. How can you check if a system has no solution or infinitely many solutions?
4. What happens when two equations represent the same line?
5. Can you graphically interpret the solution of this system?

Tip:

When solving by substitution, always simplify early to avoid unnecessary fractions!