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The problem visible in the image is:

Given the system of equations:

\[
y = \frac{3}{5}x + \frac{5}{7}
\]

and 

\[
n = 2x + y
\]

To solve for \(n\), we can substitute the expression for \(y\) from the first equation into the second equation.

### Step 1: Substitute the value of \(y\)
Substitute \( y = \frac{3}{5}x + \frac{5}{7} \) into \( n = 2x + y \):

\[
n = 2x + \left(\frac{3}{5}x + \frac{5}{7}\right)
\]

### Step 2: Combine like terms
Now, combine the terms involving \(x\):

\[
n = 2x + \frac{3}{5}x + \frac{5}{7}
\]

To add \(2x\) and \(\frac{3}{5}x\), convert \(2x\) to a fraction with the same denominator:

\[
2x = \frac{10}{5}x
\]

So, 

\[
n = \frac{10}{5}x + \frac{3}{5}x + \frac{5}{7}
\]

\[
n = \frac{13}{5}x + \frac{5}{7}
\]

### Final Expression for \(n\)
The value of \(n\) in terms of \(x\) is:

\[
n = \frac{13}{5}x + \frac{5}{7}
\]

Would you like to dive into more details or explore specific questions related to this solution?

Here are some related questions you might consider:

1. What is the value of \(n\) if \(x = 1\)?
2. How do you convert mixed fractions in such equations?
3. Can we simplify the expression for \(n\) further?
4. How would the expression for \(n\) change if the coefficients were different?
5. What are the implications of the different fractions when graphing these equations?

**Tip:** When solving systems of equations, always try to substitute one variable from one equation into the other to simplify the problem.

Explore how to solve a system of equations involving fractions step-by-step. This problem involves linear equations and substitution methods. Suitable for high school students.

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