The problem visible in the image is:

Given the system of equations:

$y = \frac{3}{5}x + \frac{5}{7}$

and

$n = 2x + y$

To solve for $n$, we can substitute the expression for $y$ from the first equation into the second equation.

Step 1: Substitute the value of $y$

Substitute $y = \frac{3}{5}x + \frac{5}{7}$ into $n = 2x + y$:

$n = 2x + \left(\frac{3}{5}x + \frac{5}{7}\right)$

Step 2: Combine like terms

Now, combine the terms involving $x$:

$n = 2x + \frac{3}{5}x + \frac{5}{7}$

To add $2x$ and $\frac{3}{5}x$, convert $2x$ to a fraction with the same denominator:

$2x = \frac{10}{5}x$

So,

$n = \frac{10}{5}x + \frac{3}{5}x + \frac{5}{7}$

$n = \frac{13}{5}x + \frac{5}{7}$

Final Expression for $n$

The value of $n$ in terms of $x$ is:

$n = \frac{13}{5}x + \frac{5}{7}$

Would you like to dive into more details or explore specific questions related to this solution?

Here are some related questions you might consider:

1. What is the value of $n$ if $x = 1$?
2. How do you convert mixed fractions in such equations?
3. Can we simplify the expression for $n$ further?
4. How would the expression for $n$ change if the coefficients were different?
5. What are the implications of the different fractions when graphing these equations?

Tip: When solving systems of equations, always try to substitute one variable from one equation into the other to simplify the problem.