At the fair, I bought 6 erasers and 2 pens for ₹ 15. If I could buy more than 4 erasers for ₹ 14 than pens for ₹ 9, then price of one was?

To find the price of one eraser and one pen, we can set up a system of equations based on the given information.

Let:
- \( e \) be the price of one eraser.
- \( p \) be the price of one pen.

From the problem, we have the following information:

1. The cost of 6 erasers and 2 pens is ₹ 15:
   \[
   6e + 2p = 15
   \]

2. The cost of more than 4 erasers is ₹ 14 and the cost of pens is ₹ 9. Since "more than 4 erasers" isn't specific, we will assume they mean 4 erasers:
   \[
   4e = 14 \implies e = 3.5
   \]

Using \( e = 3.5 \), substitute into the first equation:
   \[
   6(3.5) + 2p = 15
   \]
   \[
   21 + 2p = 15
   \]
   \[
   2p = 15 - 21
   \]
   \[
   2p = -6
   \]
   \[
   p = -3
   \]

However, having a negative price for the pen does not make sense, so we need to reevaluate the problem conditions or consider an alternative interpretation.

Assuming the conditions might imply cumulative costs rather than individual items:

Let's reanalyze the conditions:

1. \( 6e + 2p = 15 \)

2. If 4 erasers cost ₹ 14:
   \[
   4e = 14 \implies e = 3.5
   \]

The problem's consistency suggests:
Using \( e = 3.5 \):

\( 6(3.5) + 2p = 15 \)
\[
21 + 2p = 15 \\
2p = 15 - 21 \\
2p = -6 \\
p = -3
\]

**Verification:**

Given conditions suggest reviewing:
\(
6(3.5) + 2p = 15 \\
21 + 2p = 15 \\
2p = -6 \\
p = -3
\)
If \( \text{price ≠ -3}\), reassess problem consistency or reinterpret fair eraser, pen price:
Potential restate.

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### Relative Questions:

1. How might cumulative pricing affect equations, interpretations?
2. Do conditions imply combination costs rather than individual?
3. How reassess unit price constraints alter outcomes?
4. Confirm consistent steps?
5. Could alternative costs fit problem parameters?
6. Verify computation process for potential errors?
7. Address unit pricing framework assumptions?
8. Fair pricing insights derived?

**Tip:** Always verify if assumptions align with problem context to ensure accurate pricing solutions.

Learn how to solve a system of equations involving the purchase of erasers and pens at a fair. This problem covers linear equations and system-solving techniques. Suitable for students in Grades 7-9.

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