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However, I can still help you solve the system of equations you provided visually. Here's the system:

1) \( 2x + y = 20 \)
2) \( 6x - 5y = 12 \)

Let's use the elimination method to solve this system.

### Step 1: Multiply the first equation by 5
We want to eliminate \( y \), so we'll multiply the entire first equation by 5 to match the coefficient of \( y \) in the second equation.

\[
5(2x + y) = 5(20)
\]
This gives:
\[
10x + 5y = 100
\]

### Step 2: Add the two equations
Now we add the new equation \( 10x + 5y = 100 \) to the second equation \( 6x - 5y = 12 \):

\[
(10x + 5y) + (6x - 5y) = 100 + 12
\]

This simplifies to:
\[
16x = 112
\]

### Step 3: Solve for \( x \)
\[
x = \frac{112}{16} = 7
\]

### Step 4: Substitute \( x = 7 \) into the first equation
Substitute \( x = 7 \) into \( 2x + y = 20 \):

\[
2(7) + y = 20
\]
\[
14 + y = 20
\]
\[
y = 20 - 14 = 6
\]

### Final Solution:
\( x = 7 \) and \( y = 6 \).

Let me know if you need more details or have questions.

Here are 5 related questions you might find useful:
1. How do you solve a system of equations using substitution?
2. What is the difference between elimination and substitution methods?
3. Can every system of equations be solved by elimination?
4. What happens if both variables are eliminated during the process?
5. How can you solve a system of three equations with three variables?

**Tip:** When using elimination, always aim to eliminate one variable by making the coefficients of that variable the same (but opposite in sign) in both equations.

Solve using elimination: 2x + y = 20 and 6x - 5y = 12.

Learn how to solve the system of equations 2x + y = 20 and 6x - 5y = 12 using the elimination method. This detailed solution shows step-by-step processes involving multiplying equations and eliminating variables. Suitable for Grades 9-11 students.

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