To solve \( \sin(x) = \frac{21}{32} \) in degree mode, we can find the value of \( x \) using the inverse sine function:

\[
x = \sin^{-1}\left(\frac{21}{32}\right)
\]

Now let's calculate the value of \( x \) in degrees.The value of \( x \) in degrees is approximately \( 41.01^\circ \).

Would you like more details or have any questions?

Here are some related questions:
1. How do you solve for \( x \) in \( \cos(x) = \frac{3}{5} \)?
2. What is the general solution for \( \sin(x) = 0.5 \) in degrees?
3. How can you find the exact value of \( \sin^{-1}(0.6) \) without a calculator?
4. How does the sine function behave in different quadrants?
5. What is the range of the inverse sine function?

**Tip:** When solving trigonometric equations, always check the mode of your calculator (degree or radian) to match the context of the problem.

Discover how to solve sin(x) = 21/32 in degree mode using the inverse sine function. This problem covers core trigonometric concepts, including the sine function and how to calculate angles using inverse sine. Suitable for students in Grades 10-12.

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