Find the value of s in the interval left bracket 0 comma StartFraction pi Over 2 EndFraction right bracket
 that satisfies the given statement.
Bold sin sequals0.6623
Question content area bottom
Part 1
sequals
  
enter your response here radians
​(Round to four decimal places as​ needed.)

We are asked to find the value of \( s \) in the interval \( \left( 0, \frac{\pi}{2} \right) \) such that:

\[
\sin(s) = 0.6623
\]

To find \( s \), we take the inverse sine (also known as arcsin) of 0.6623:

\[
s = \arcsin(0.6623)
\]

Let's calculate this and round to four decimal places.

The value of \( s \) that satisfies \( \sin(s) = 0.6623 \) in the interval \( \left( 0, \frac{\pi}{2} \right) \) is approximately \( s = 0.7239 \) radians.

Would you like any further details or explanations on this? Here are some related questions you might explore:

1. How do you compute the arcsine function?
2. What is the range of the arcsine function?
3. How can we convert radians to degrees?
4. How does the sine function behave in different quadrants?
5. What is the meaning of rounding to four decimal places in a mathematical context?

**Tip:** Always make sure your calculator is set to the correct mode (radians or degrees) when working with trigonometric functions!

Find the value of s in the interval (0, π/2) that satisfies the given statement: sin(s) = 0.6623. Round to four decimal places as needed.

Learn how to solve for s in the equation sin(s) = 0.6623, where s is in the interval (0, π/2). This trigonometry problem focuses on the inverse sine function and rounding to four decimal places. Suitable for high school students (Grades 10-12).

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