Math Problem Statement

Do number 1

Do number 1

Solution

To solve question 1:

The problem states that ABCDEF\triangle ABC \sim \triangle DEF, meaning the triangles are similar. For similar triangles, the ratios of corresponding sides are equal.

Corresponding side pairs:

  • AB:DEAB : DE
  • AC:DFAC : DF
  • BC:EFBC : EF

Given:

  • AB=7cmAB = 7 \, \text{cm}
  • AC=6cmAC = 6 \, \text{cm}
  • BC=10cmBC = 10 \, \text{cm}
  • DE=4cmDE = 4 \, \text{cm} (one corresponding side provided)

We need to find EFEF and DFDF.


Step 1: Ratio of similarity

Using AB:DEAB : DE, the ratio is: ABDE=74.\frac{AB}{DE} = \frac{7}{4}.

Thus, the ratio of similarity is 74\frac{7}{4}. This same ratio applies to the other pairs of corresponding sides.


Step 2: Find EFEF

Using BC:EFBC : EF, we solve for EFEF: BCEF=74.\frac{BC}{EF} = \frac{7}{4}.

Substitute BC=10BC = 10: 10EF=74.\frac{10}{EF} = \frac{7}{4}.

Cross-multiply: 7EF=410.7 \cdot EF = 4 \cdot 10.

7EF=40    EF=4075.7cm.7 \cdot EF = 40 \implies EF = \frac{40}{7} \approx 5.7 \, \text{cm}.


Step 3: Find DFDF

Using AC:DFAC : DF, we solve for DFDF: ACDF=74.\frac{AC}{DF} = \frac{7}{4}.

Substitute AC=6AC = 6: 6DF=74.\frac{6}{DF} = \frac{7}{4}.

Cross-multiply: 7DF=46.7 \cdot DF = 4 \cdot 6.

7DF=24    DF=2473.4cm.7 \cdot DF = 24 \implies DF = \frac{24}{7} \approx 3.4 \, \text{cm}.


Final Answer:

  • EF=5.7cmEF = 5.7 \, \text{cm}
  • DF=3.4cmDF = 3.4 \, \text{cm}

Would you like a detailed breakdown or help with another question?


Related Questions:

  1. How are similar triangles defined, and what properties do they share?
  2. How do you find the ratio of similarity between two triangles?
  3. What other geometric methods can be used to verify similarity?
  4. How would the problem change if DEDE was not provided?
  5. What are some real-life applications of similar triangles?

Tip:

When working with similar triangles, always align the corresponding sides properly to avoid errors in ratio calculation!

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Math Problem Analysis

Mathematical Concepts

Similar Triangles
Ratios of Corresponding Sides

Formulas

Similarity Ratio = Corresponding Side Lengths Ratio
Cross Multiplication for Proportional Ratios

Theorems

Triangle Similarity Theorem

Suitable Grade Level

Grades 7-9