From the graph you provided, let's follow these steps to evaluate and solve:

Part a) $f(0)$:

To evaluate $f(0)$, we look at the value of the function where $x = 0$. From the graph, when $x = 0$, the function's value appears to be approximately $1$. Therefore: $f(0) = 1$

Part b) Solve for $f(x) = -1$:

We now need to find where the graph intersects the line $y = -1$. From the graph, we see two points where the graph reaches $y = -1$. These points look like they occur approximately at $x = -2$ and $x = 2$.

Thus, the solutions to $f(x) = -1$ are:

1. $x = -2$
2. $x = 2$

Since the problem asks for the larger value in the second field, the answers are:

• First field: $-2$
• Second field: $2$

Final answers:

a) $f(0) = 1$

b) $f(-2) = -1$, $f(2) = -1$

Would you like any additional details on the steps taken? Here are five related questions that might help you explore this further:

1. How do we find exact values of intersection points algebraically?
2. What are the conditions for a quadratic function to have two roots?
3. How can we find the vertex of this function?
4. How can transformations affect the graph of a function?
5. What would happen if we shift the graph up or down by 2 units?

Tip: Always ensure to check both the $x$-axis and $y$-axis when solving for specific values on a graph to avoid confusion with signs or approximations.