Math Problem Statement

Solve x^2 - 4x - 21 = 0 by factorizing.

Solution

The equation in the image is:

x24x21=0x^2 - 4x - 21 = 0

We are asked to solve this quadratic equation by factorizing.

Step-by-step solution:

  1. Identify the quadratic form: The equation is in the standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0, where:

    • a=1a = 1 (coefficient of x2x^2),
    • b=4b = -4 (coefficient of xx),
    • c=21c = -21 (constant term).
  2. Find factors of the constant term 21-21: We are looking for two numbers that multiply to 21-21 and add to 4-4. The factors of 21-21 are:

    • 33 and 7-7, because: 3×(7)=21and3+(7)=43 \times (-7) = -21 \quad \text{and} \quad 3 + (-7) = -4
  3. Write the factored form: Using these factors, we can rewrite the quadratic equation as: (x+3)(x7)=0(x + 3)(x - 7) = 0

  4. Solve for xx: To find the solutions, set each factor equal to zero: x+3=0orx7=0x + 3 = 0 \quad \text{or} \quad x - 7 = 0 Solving these gives: x=3orx=7x = -3 \quad \text{or} \quad x = 7

Final solution:

The solutions to the equation x24x21=0x^2 - 4x - 21 = 0 are x=3x = -3 and x=7x = 7.

Would you like further clarification on this process or more details?

Here are five related questions to deepen your understanding:

  1. How do you solve a quadratic equation if it cannot be factored?
  2. What is the quadratic formula, and when should you use it?
  3. How can you verify the solutions to a quadratic equation?
  4. What are the key characteristics of a quadratic function's graph?
  5. What happens when the discriminant of a quadratic equation is negative?

Tip:

When factorizing quadratic equations, always check that the product of the factors equals the constant term and that their sum equals the coefficient of the linear term.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Factorization

Formulas

Quadratic equation formula ax^2 + bx + c = 0

Theorems

Factorization method for solving quadratic equations

Suitable Grade Level

Grades 8-10