Math Problem Statement
Solution
The problem you uploaded asks for two things:
-
Solve the equation: for such that the inequality is also satisfied.
-
Show that the function: is increasing at .
Step 1: Solving the equation
The equation is: Multiplying both sides by to eliminate the fraction gives: Rearranging this, we get a quadratic equation in terms of : Let . This simplifies to: We can solve this quadratic using the quadratic formula: Thus, or .
Since is approximately 5.83, the second solution is negative, which is not possible for . Hence, the only valid solution is: Taking the square root of both sides:
Step 2: Checking the inequality
The inequality to check is . Factorizing this, we get: The critical points occur when or .
Testing intervals:
- For , the expression is positive.
- For , the expression is negative.
- For , the expression is negative.
- For , the expression is positive.
Thus, when or .
Step 3: Verifying at that the function is increasing
To show that is increasing at , we take the derivative: At : This means the function is not increasing or decreasing at , as the derivative equals zero (it has a critical point).
Would you like more details or have any further questions?
Here are 5 related questions to explore further:
- How do we solve quadratic equations in general?
- What does the sign of the derivative tell us about a function's behavior?
- What is the graphical interpretation of the function ?
- How can we determine intervals where a function is increasing or decreasing?
- How do we solve equations involving higher powers (quartic equations)?
Tip: Always verify the domain of solutions when dealing with square roots or fractions in equations!
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Math Problem Analysis
Mathematical Concepts
Algebra
Quadratic Equations
Inequalities
Derivatives
Functions
Formulas
x^2 - 9/x^2 = 10
x^3 - 3x > 0
y' = 3x^2 - 3 (derivative of y = x^3 - 3x)
Theorems
Quadratic formula
First derivative test (for increasing or decreasing functions)
Suitable Grade Level
Grades 10-12