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To solve the problem, we need to find how many gallons of gas Jackson will use for a trip to Mount Highmore, assuming he uses gas at the same rate as his trip to Crabclaw Beach.

### Given information:
- Last weekend, Jackson drove **80 miles** and used **4 gallons** of gas.
- This weekend, he will drive **100 miles**.
- The gas consumption rate is the same for both trips.

### Step 1: Set up the proportion
The proportion compares the distance and gas consumption from both trips:
\[
\frac{80 \text{ miles}}{4 \text{ gallons}} = \frac{100 \text{ miles}}{x \text{ gallons}}
\]
Where \(x\) is the number of gallons of gas Jackson will use for 100 miles.

### Step 2: Solve for \(x\)
To solve for \(x\), use cross-multiplication:
\[
80 \times x = 100 \times 4
\]
\[
80x = 400
\]
Now divide both sides by 80:
\[
x = \frac{400}{80} = 5
\]

### Conclusion:
Jackson will use **5 gallons** of gas to drive 100 miles to Mount Highmore.

Would you like more details or have any questions? Here are 5 related questions:

1. How can we calculate the gas mileage rate (miles per gallon)?
2. What if Jackson drives 150 miles at the same gas rate? How many gallons will he use?
3. How would the calculation change if his gas mileage decreased for the second trip?
4. Can you set up the proportion in a different way and still get the same result?
5. What is the average gas mileage rate for the entire trip to both locations?

**Tip**: Cross-multiplication is a handy tool to solve proportions like these quickly!

Jackson loves to take day trips during weekends. Last weekend, he drove 80 miles to Crabclaw Beach. He used 4 gallons of gas to get there. This weekend, he will drive 100 miles to get to Mount Highmore. If he uses gas at the same rate, how many gallons of gas will Jackson use to get to Mount Highmore?

Learn how to solve a proportions word problem involving gas consumption. Jackson drove 80 miles using 4 gallons of gas. Find out how many gallons he will use for a 100-mile trip to Mount Highmore. Ideal for students in Grades 6-7.

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