Math Problem Statement

Can you solve this by Arithmetic sequence

Solution

Sure, let's analyze the sequences in the provided image to determine if they follow an arithmetic sequence and solve for the common difference dd. Then, we will find the next three terms for each sequence.

Sequence 1: 14, 25, 36, 47, ...

First, we check if the sequence is arithmetic by calculating the differences between consecutive terms:

  • 2514=1125 - 14 = 11
  • 3625=1136 - 25 = 11
  • 4736=1147 - 36 = 11

The common difference dd is 11.

The next three terms: 47+11=5847 + 11 = 58 58+11=6958 + 11 = 69 69+11=8069 + 11 = 80

Thus, the sequence continues as: 14,25,36,47,58,69,8014, 25, 36, 47, 58, 69, 80

Sequence 2: -34, -29, -24, -19, ...

Check the differences:

  • 29(34)=5-29 - (-34) = 5
  • 24(29)=5-24 - (-29) = 5
  • 19(24)=5-19 - (-24) = 5

The common difference dd is 5.

The next three terms: 19+5=14-19 + 5 = -14 14+5=9-14 + 5 = -9 9+5=4-9 + 5 = -4

Thus, the sequence continues as: 34,29,24,19,14,9,4-34, -29, -24, -19, -14, -9, -4

Sequence 3: 27, 17, 7, -3, ...

Check the differences:

  • 1727=1017 - 27 = -10
  • 717=107 - 17 = -10
  • 37=10-3 - 7 = -10

The common difference dd is -10.

The next three terms: 310=13-3 - 10 = -13 1310=23-13 - 10 = -23 2310=33-23 - 10 = -33

Thus, the sequence continues as: 27,17,7,3,13,23,3327, 17, 7, -3, -13, -23, -33

Sequence 4: 12,15,18,111,\frac{1}{2}, \frac{1}{5}, \frac{1}{8}, \frac{1}{11},

Check the differences:

  • 1512=2510=310\frac{1}{5} - \frac{1}{2} = \frac{2 - 5}{10} = -\frac{3}{10}
  • 1815=5840=340\frac{1}{8} - \frac{1}{5} = \frac{5 - 8}{40} = -\frac{3}{40}
  • 11118=81188=388\frac{1}{11} - \frac{1}{8} = \frac{8 - 11}{88} = -\frac{3}{88}

Here, the common difference is not consistent, so it is not an arithmetic sequence.

Sequence 5: x,2,x+4x, 2, x + 4

Check the differences:

  • 2x2 - x
  • (x+4)2=x+2(x + 4) - 2 = x + 2

To find xx, we set the differences equal since they must be the same for an arithmetic sequence: 2x=x+22 - x = x + 2 2x=x+22 - x = x + 2 2=2x+22 = 2x + 2 0=2x0 = 2x x=0x = 0

So, the sequence becomes: 0,2,40, 2, 4

The next three terms: 4+2=64 + 2 = 6 6+2=86 + 2 = 8 8+2=108 + 2 = 10

Thus, the sequence continues as: 0,2,4,6,8,100, 2, 4, 6, 8, 10

Would you like any further details or have any questions?

Here are 8 related questions to expand on the previous information:

  1. Can you identify other types of sequences apart from arithmetic ones?
  2. How can you determine if a sequence is geometric instead of arithmetic?
  3. What are the formulas for finding the nnth term of an arithmetic sequence?
  4. How would the approach differ for sequences with fractional or decimal common differences?
  5. Can you provide an example of a quadratic sequence and its general formula?
  6. How do arithmetic sequences relate to real-world applications?
  7. What is the sum of the first nn terms in an arithmetic sequence?
  8. How can arithmetic sequences be used to solve algebraic problems?

Tip: For verifying if a sequence is arithmetic, always check if the difference between consecutive terms remains constant throughout the sequence.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences

Formulas

Arithmetic sequence formula: \( a_n = a_1 + (n-1)d \)

Theorems

-

Suitable Grade Level

Grades 7-9