The community pool had an event to raise money. The price to go in the pool was $6 for adults and $2 for students 220 people went in the pool. The event raised $720. How many adults went in the pool?

Let's use algebra to solve this problem.

Let:
- $ x $ be the number of adults who went to the pool.
- $ y $ be the number of students who went to the pool.

We have two pieces of information that can be translated into equations:

1. **Total number of people**:  
   $ x + y = 220 $
   
2. **Total money raised**:  
   $ 6x + 2y = 720 $

### Step 1: Solve the first equation for $ y $:
\[
y = 220 - x
\]

### Step 2: Substitute $ y $ in the second equation:
\[
6x + 2(220 - x) = 720
\]

### Step 3: Distribute and simplify:
\[
6x + 440 - 2x = 720
\]
\[
4x + 440 = 720
\]

### Step 4: Subtract 440 from both sides:
\[
4x = 280
\]

### Step 5: Divide by 4:
\[
x = 70
\]

So, **70 adults** went to the pool.

### Verification:
If 70 adults attended, then $ y = 220 - 70 = 150 $ students attended. 
Now, checking the total money:
\[
6(70) + 2(150) = 420 + 300 = 720
\]

The solution is correct. 70 adults went to the pool.

Would you like further details or have any questions?

Here are some related questions:

1. How would the problem change if the ticket prices were different?
2. What if the number of attendees increased to 300 but the total money raised stayed the same?
3. How would you calculate the number of adults if the problem didn't give the total amount raised?
4. What would happen if a different combination of adults and students attended?
5. How could this problem be solved using a different method?

**Tip:** Always double-check your solution by substituting the values back into the original equations to ensure they satisfy all conditions.

Learn how to solve the problem of determining how many adults went to a pool event based on ticket sales. This problem involves algebraic equations, specifically linear equations with two variables. Suitable for students in Grades 6-8.

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