Math Problem Statement

FIND R¹=? I¹=? V¹=? I¹=? I²=? I³=?

FIND R_T=?, I_T=?, V_1=?, I_1=?, I_2=?, I_3=? for a circuit with 4 resistors in parallel: 5Ω, 2Ω, 7Ω, and 8Ω connected to a 20V source.

Solution

The circuit in the image is a parallel combination of resistors connected to a 20V source. Here's how we can solve for each of the unknowns:

1. Finding RTR_T (Total Resistance)

The total resistance RTR_T in a parallel circuit is found using the formula:

1RT=1R1+1R2+1R3+1R4\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4}

Where:

  • R1=5ΩR_1 = 5 \, \Omega
  • R2=2ΩR_2 = 2 \, \Omega
  • R3=7ΩR_3 = 7 \, \Omega
  • R4=8ΩR_4 = 8 \, \Omega

Substitute the values:

1RT=15+12+17+18\frac{1}{R_T} = \frac{1}{5} + \frac{1}{2} + \frac{1}{7} + \frac{1}{8}

We need to compute this expression:

1RT=0.2+0.5+0.142857+0.125\frac{1}{R_T} = 0.2 + 0.5 + 0.142857 + 0.125

1RT=0.967857\frac{1}{R_T} = 0.967857

RT10.9678571.032ΩR_T \approx \frac{1}{0.967857} \approx 1.032 \, \Omega

So, the total resistance is approximately RT=1.032ΩR_T = 1.032 \, \Omega.


2. Finding ITI_T (Total Current)

The total current ITI_T is found using Ohm's law:

IT=VRTI_T = \frac{V}{R_T}

Where V=20VV = 20 \, \text{V} and RT=1.032ΩR_T = 1.032 \, \Omega.

IT=201.03219.38AI_T = \frac{20}{1.032} \approx 19.38 \, \text{A}

So, the total current is IT19.38AI_T \approx 19.38 \, \text{A}.


3. Finding V1V_1 (Voltage across each resistor)

In a parallel circuit, the voltage across each resistor is the same and equal to the source voltage. Therefore:

V1=V2=V3=V4=20VV_1 = V_2 = V_3 = V_4 = 20 \, \text{V}


4. Finding I1I_1, I2I_2, I3I_3, and I4I_4

We can use Ohm's law again to find the current through each resistor:

I1=VR1,I2=VR2,I3=VR3,I4=VR4I_1 = \frac{V}{R_1}, \quad I_2 = \frac{V}{R_2}, \quad I_3 = \frac{V}{R_3}, \quad I_4 = \frac{V}{R_4}

Where V=20VV = 20 \, \text{V}.

For I1I_1 (through R1=5ΩR_1 = 5 \, \Omega):

I1=205=4AI_1 = \frac{20}{5} = 4 \, \text{A}

For I2I_2 (through R2=2ΩR_2 = 2 \, \Omega):

I2=202=10AI_2 = \frac{20}{2} = 10 \, \text{A}

For I3I_3 (through R3=7ΩR_3 = 7 \, \Omega):

I3=2072.857AI_3 = \frac{20}{7} \approx 2.857 \, \text{A}

For I4I_4 (through R4=8ΩR_4 = 8 \, \Omega):

I4=208=2.5AI_4 = \frac{20}{8} = 2.5 \, \text{A}


Final Answers:

  • RT1.032ΩR_T \approx 1.032 \, \Omega
  • IT19.38AI_T \approx 19.38 \, \text{A}
  • V1=V2=V3=V4=20VV_1 = V_2 = V_3 = V_4 = 20 \, \text{V}
  • I1=4AI_1 = 4 \, \text{A}
  • I2=10AI_2 = 10 \, \text{A}
  • I32.857AI_3 \approx 2.857 \, \text{A}
  • I4=2.5AI_4 = 2.5 \, \text{A}

Would you like more details on any part of the solution?

Further Related Questions:

  1. How would the total current change if one of the resistors was removed?
  2. What is the power consumed by each resistor?
  3. How does the total resistance change if another resistor is added in parallel?
  4. What is the effect on the current if the source voltage is increased to 30V?
  5. How can we find the equivalent resistance in a series circuit?

Tip:

In a parallel circuit, adding more resistors decreases the total resistance, while in a series circuit, it increases the total resistance.

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Math Problem Analysis

Mathematical Concepts

Ohm's Law
Parallel Circuits
Current and Voltage Calculations

Formulas

1/R_T = 1/R_1 + 1/R_2 + 1/R_3 + 1/R_4
I_T = V/R_T
I_n = V/R_n (for each resistor in parallel)

Theorems

Ohm's Law
Parallel Resistance Formula

Suitable Grade Level

Grades 10-12