Math Problem Statement

Diketahui rangkaian hambatan berikut: 1 ohm, 2 ohm, 4 ohm (dua resistor sejajar), dan 5 ohm. Jika rangkaian ini dihubungkan dengan baterai 15 V, besar kuat arus yang mengalir dalam rangkaian tersebut berapa?

Solution

The circuit shown is a combination of series and parallel resistors. Let's break it down and calculate the total resistance step by step, followed by the current using Ohm's law.

Step-by-step solution:

  1. Identify the structure:

    • The resistors are arranged in a combination of series and parallel connections.
    • In the middle, there are two 4-ohm resistors connected in parallel.
  2. Calculate the equivalent resistance for the two 4-ohm resistors in parallel: For resistors R1R_1 and R2R_2 in parallel, the equivalent resistance ReqR_{eq} is given by: 1Req=1R1+1R2\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} Substituting R1=4ΩR_1 = 4 \, \Omega and R2=4ΩR_2 = 4 \, \Omega: 1Req=14+14=24=12\frac{1}{R_{eq}} = \frac{1}{4} + \frac{1}{4} = \frac{2}{4} = \frac{1}{2} So, the equivalent resistance of the parallel section is: Req=2ΩR_{eq} = 2 \, \Omega

  3. Simplify the circuit:

    • The two 4-ohm resistors are now replaced by a single 2-ohm resistor.
    • This 2-ohm resistor is in series with the 2-ohm resistor on the left, the 1-ohm resistor on the far left, and the 5-ohm resistor on the right.
  4. Sum the resistances in series: In a series circuit, the total resistance is the sum of all the resistances. So the total resistance RtotalR_{total} is: Rtotal=1Ω+2Ω+2Ω+5Ω=10ΩR_{total} = 1 \, \Omega + 2 \, \Omega + 2 \, \Omega + 5 \, \Omega = 10 \, \Omega

  5. Find the current using Ohm's law: Ohm's law states: I=VRI = \frac{V}{R} Here, V=15VV = 15 \, \text{V} (the battery voltage), and R=10ΩR = 10 \, \Omega (the total resistance). So the current is: I=1510=1.5AI = \frac{15}{10} = 1.5 \, \text{A}

Final Answer:

The current flowing through the circuit is 1.5A1.5 \, \text{A}.

Would you like any more details or clarifications?

Here are five related questions for further exploration:

  1. How would the total resistance change if one of the 4-ohm resistors was removed?
  2. What would happen to the current if the voltage of the battery was increased to 20 V?
  3. If the resistors were all connected in parallel, how would the total resistance be calculated?
  4. How does the equivalent resistance change if the 5-ohm resistor was doubled to 10 ohms?
  5. What effect does adding another resistor in series have on the overall current in the circuit?

Tip: Always remember to simplify the circuit step-by-step by identifying parallel and series connections when calculating total resistance.

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Math Problem Analysis

Mathematical Concepts

Electric Circuits
Resistors
Ohm's Law
Series and Parallel Circuits

Formulas

Ohm's Law: I = V / R
Parallel Resistor Formula: 1/R_eq = 1/R1 + 1/R2
Series Resistor Formula: R_total = R1 + R2 + ... + Rn

Theorems

Ohm's Law
Series and Parallel Resistance Theorem

Suitable Grade Level

High School Physics (Grade 10-12)