This is a question about an electrical circuit. We have four resistors, all of the same resistance $R$, and they are connected as shown, with a power supply of 10 V. The task is to find the current through resistor $R_1$, which is part of this arrangement.

From the image, it appears that the four resistors are arranged in a parallel configuration. The total resistance for resistors in parallel can be calculated using the formula:

$\frac{1}{R_{\text{total}}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} + \frac{1}{R}$

Simplifying this:

$\frac{1}{R_{\text{total}}} = \frac{4}{R}$

Thus, the total resistance $R_{\text{total}}$ is:

$R_{\text{total}} = \frac{R}{4}$

Now, using Ohm's law, $V = I \times R$, we can solve for the total current $I_{\text{total}}$:

$I_{\text{total}} = \frac{V}{R_{\text{total}}} = \frac{10}{\frac{R}{4}} = \frac{10 \times 4}{R} = \frac{40}{R}$

Since the current is equally distributed among the four resistors in parallel, the current through each resistor, including $R_1$, is:

$I_1 = \frac{I_{\text{total}}}{4} = \frac{40}{4R} = \frac{10}{R}$

Now, we substitute $R = 5 \, \Omega$:

$I_1 = \frac{10}{5} = 2 \, \text{A}$

So, the current through resistor $R_1$ is 2 A.

The correct answer is C) 2 A.

Would you like further clarification or details about this calculation?

Here are some related questions:

1. How do you calculate the total current in a parallel circuit?
2. What is the relationship between resistance and current in a parallel configuration?
3. How do you determine the current in a resistor in a parallel circuit?
4. What happens to the total resistance when more resistors are added in parallel?
5. How does the power supply voltage affect the current in a circuit?

Tip: In a parallel circuit, the voltage across each resistor is the same, so the current is inversely proportional to the resistance.