The image shows a mathematical word problem written in Hindi. Here's the transcription of the problem:

Problem: "एक आदमी अपनी आय का 40% खर्च करता है। जीवित रहने के लिए भोजन में खर्च हुए तिहाई के साथ उसी बची हुई राशि में 3+1/3 का वृद्धि होती है। उसके उसी आय में 16 रू. की वृद्धि होती है। वह राशि कितनी थी?"

Translation: "A man spends 40% of his income. For food expenses, 1/3 of the remaining amount plus an increase of $3 + \frac{1}{3}$. There is an increase of ₹16 in his income. What was the original amount?"

Breakdown of the Problem:

1. The man spends 40% of his income.
2. He uses 1/3 of the remaining amount on food.
3. There is an increase of $3 + \frac{1}{3}$ in the remaining amount.
4. The increase results in ₹16 more in his income.

Let me solve this for you step by step.

Let the original income be $x$.

1. Expenses:

   • The man spends 40%, so the remaining income is $60\%$ of $x$, which is $0.6x$.

2. Food Expenses:

   • He spends $\frac{1}{3}$ of $0.6x$ on food. This means the food expense is $\frac{1}{3} \times 0.6x = 0.2x$.

3. Remaining Income After Food:

   • The remaining amount after food expenses is $0.6x - 0.2x = 0.4x$.

4. Increase:

   • The remaining amount increases by $3 + \frac{1}{3}$, i.e., $3 \frac{1}{3} = \frac{10}{3}$.
   • The total increase is ₹16, so the relation becomes: $\frac{10}{3} \times 0.4x = 16$

5. Solve for $x$: Now we can solve for $x$ from the equation.

Let me calculate this next.The original income of the man was ₹12.

Would you like a more detailed explanation or have any other questions?

Here are some related questions you might find useful:

1. What would happen if his expenses were 50% instead of 40%?
2. How would the equation change if the increase in income was ₹20 instead of ₹16?
3. Can you determine the man's total expenses if he increases his food spending by ₹5?
4. What would the total food expense be if his income doubled?
5. If the increase $3 + \frac{1}{3}$ was replaced by a fixed ₹10, what would the new income be?

Tip: When solving word problems, it's often helpful to translate each part into mathematical equations to simplify the solution process!