(((((1+1)+(1+1))+((1+1)+(1+1)))+(((1+1)+(1+1))+((1+1)+(1+1))))+((((1+1)+(1+1))+((1+1)+(1+1)))+(((1+1)+(1+1))+((1+1)+(1+1)))))$$  $$

To solve the given expression:

\[
(((((1+1)+(1+1))+((1+1)+(1+1)))+(((1+1)+(1+1))+((1+1)+(1+1))))+((((1+1)+(1+1))+((1+1)+(1+1)))+(((1+1)+(1+1))+((1+1)+(1+1)))))
\]

we first simplify each pair of parentheses starting from the innermost ones.

1. Calculate $1+1$:

\[
1+1 = 2
\]

2. Substitute 2 into the expression wherever $1+1$ appears:

\[
(((((2)+(2))+((2)+(2)))+(((2)+(2))+((2)+(2))))+((((2)+(2))+((2)+(2)))+(((2)+(2))+((2)+(2)))))
\]

3. Now calculate $2+2$:

\[
2+2 = 4
\]

4. Substitute 4 into the expression wherever $2+2$ appears:

\[
((((4)+(4))+(4)+(4)))+(((4)+(4))+(4)+(4)))+(((4)+(4))+(4)+(4)))+(((4)+(4))+(4)+(4)))
\]

5. Simplify each pair of $4+4$:

\[
4+4 = 8
\]

6. Substitute 8 into the expression wherever $4+4$ appears:

\[
((((8)+(8))+(8)+(8)))+(((8)+(8))+(8)+(8)))+(((8)+(8))+(8)+(8)))+(((8)+(8))+(8)+(8)))
\]

7. Simplify each pair of $8+8$:

\[
8+8 = 16
\]

8. Substitute 16 into the expression wherever $8+8$ appears:

\[
((((16)+(16))+(16)+(16)))+(((16)+(16))+(16)+(16)))+(((16)+(16))+(16)+(16)))+(((16)+(16))+(16)+(16)))
\]

9. Simplify each pair of $16+16$:

\[
16+16 = 32
\]

10. Substitute 32 into the expression wherever $16+16$ appears:

\[
((((32)+(32))+(32)+(32)))+(((32)+(32))+(32)+(32)))+(((32)+(32))+(32)+(32)))+(((32)+(32))+(32)+(32)))
\]

11. Finally, simplify each pair of $32+32$:

\[
32+32 = 64
\]

Thus, the final result of the expression is:

\[
64
\]

Do you want any more details or have any questions?

Here are some related questions you might find interesting:

1. What is the result of $ ((((3+3)+(3+3))+((3+3)+(3+3)))+(((3+3)+(3+3))+((3+3)+(3+3)))) $?
2. How do you solve nested parentheses expressions?
3. What is the value of $ ((((5+5)+(5+5))+((5+5)+(5+5)))+(((5+5)+(5+5))+((5+5)+(5+5)))) $?
4. How can we use the distributive property to simplify expressions?
5. What is the importance of the order of operations in solving expressions?
6. Can you explain how to handle more complex expressions with exponents?
7. What is the process for solving expressions with both addition and multiplication?
8. How do we solve expressions involving variables?

**Tip:** Always start solving nested expressions from the innermost parentheses and work your way outward to avoid mistakes.

Learn how to solve the nested parentheses expression (((1+1)+(1+1))+((1+1)+(1+1)))+((((1+1)+(1+1))+((1+1)+(1+1)))+(((1+1)+(1+1))+((1+1)+(1+1)))) step-by-step with detailed arithmetic operations. Suitable for students in Grades 3-5.

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